If two tangent segments to a circle share a
common endpoint outside a circle, then the two segments are congruent. This
is according to the intersection of two tangent theorem. The theorem states
that given a circle, if X is any point
within outside the circle and if Y and Z are points such that XY and XZ are
tangents to the circle, then XY is equal to XZ.
<span> </span>
<span>87 less than the quotient of an unknown number and 43 is -75
Converting that to mathematical equation:
87 - (x / 43) = -75
Evaluating the equation, we can the value of x.
87 - (x/43) = -75
-x/43 = -75 - 87
-x/43 = -162
-x = -6966
x = 6966</span>
1 1/2 can be rewritten as 3/2
Difference means subtraction
So we do:
3/2-1/4
To get the same denominator, we can multiply the first fraction by 2
6/4-1/4
Then we subtract the numerators and leave the denominator
So the final answer is 5/4 of 1 1/4
Hope this helps
Answer:
#carry on learning
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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
I really need this question answered
By:
I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34
Answer:
0
Step-by-step explanation: Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-20y' to each side of the equation.
15x + 20y + -20y = 0 + -20y
Combine like terms: 20y + -20y = 0
15x + 0 = 0 + -20y
15x = 0 + -20y
Remove the zero:
15x = -20y
Divide each side by '15'.
x = -1.333333333y
Simplifying
x = -1.333333333y