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3 years ago

How can you be sure the lines you constructed are parallel?

Mathematics

2 answers:

Natali5045456 [20]3 years ago

7 0

They will be strait alined with the other line perfectly

Andru [333]3 years ago

5 0

You can make sure by making sure they never ever meet

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20). If 5X = 20, then X = 4

kondaur [170]

Correct my guy. Keep up the great work

7 0

3 years ago

Read 2 more answers

Simplify the expression. 10C7 A. 1 B. 3,628,800 C. 604,800 D. 120

Sophie [7]

Answer:

Combination

Step-by-step explanation:

Here by 10C7 we actually mean, $C_{7}^{10}$

And the formula for evaluating mCn is

$=\frac{m!}{n!*(m-n)!}$

Therefore

10C7 =

$=\frac{10!}{7!*(10-7)!} \\=\frac{10!}{7!*3!} \\$

Where m! is called m factorial and can be evaluated as

m!= m*(m-1)*(m-2)*(m-3)*.......3*2*1

Hence

10!= 10*9*8......*3*2*1

7!= 7*8*6.....3*2*1

3!=3*2*1

With these we can evaluate

10C7

$=\frac{10*9*8*7*.....3*2*1}{(3*2*1)*(7*6*5....3*2*1)}\\=\frac{10*9*8}{3*2*1} \\=\frac{10*3*4}{1} \\=120$

Hence the answer is D

4 0

3 years ago

PLSSS HELP IF YOU TURLY KNOW THISS

ki77a [65]

Hello there!

Keep in mind that everything to the power of 0 equals 1.

$80^{0} =1$

Hope this helps and have a fantastic day! :)

~Just a joyful teen

$SilentNature$

5 0

3 years ago

Please answer this correctly

Tamiku [17]

0.001, 0.014, 0.1, 9.41

3 0

4 years ago

Read 2 more answers

Caleb's mother said they will drive 1 /4 hour to get there, and they will drive another 1 /4 hour back. Once they arrive, Caleb'

Nezavi [6.7K]

Answer: They are away for $2\dfrac{3}{4}\ hours$ from home.

Step-by-step explanation:

Since we have given that

Time to get there = $\dfrac{1}{4}$

Time to get back = $\dfrac{1}{4}$

Number of soccer games = 3

Time for each soccer games = $\dfrac{3}{4}$

So, total time for 3 games would be

$3\times \dfrac{3}{4}=\dfrac{9}{4}$

So, the time for which they will be away from home is given by

$\dfrac{1}{4}+\dfrac{9}{4}+\dfrac{1}4}=\dfrac{1+9+1}{4}=\dfrac{11}{4}=2\dfrac{3}{4}\ hours$

Hence, they are away for $2\dfrac{3}{4}\ hours$ from home.

3 0

4 years ago