Tow ratios that have the same value when simplified.
Hope this helps!!;)
Answer:
8: 50 hours
9: 6 inches
10: 43 cm
Step-by-step explanation:
I couldn't see the entirety of 7 because some of the page was folded, so I didn't answer it.
8: Make them equations of y=12x+450 and y=21x. Since both equal y, set them equal to each other so 21x=12x+450. Subtract 12x from both sides to get 9x=450. Divide by 9 on both sides to get 50.
9: The length equals 3w-6 and the width is just w. The perimeter would equal 2w+2(3w-6) which when factored is 2w+6w-12. Simplify to 8w-12. If P=8w-12 and we know P=36, then set the two equations equal to each other so that 8w-12=36. Add 12 to both sides to get 8w=48. Then divide both sides by 8 to get a final answer of w=6.
10. P=x+5x+8+4x-7. Simplify that to P=10x+1. We know that P=71, so set the two equations equal to each other to get 71=10x+1. Subtract 1 from both sides to get 70=10x. Divide both sides by 10 and x=7. Now substitute x in each side of the triangle and we get 7, (4*7-7), and (5*7+8). Solve all of those to get sides of 7, 21, and 43. The question asks what is the length of the longest side, so the answer would be 43.
Answer:
$25,000
Step-by-step explanation:
You already have 2,000 so all you need to do is get the other 2,000. So you would have to divide 7,000 by 100 which =70 then multiply it by 8 and you get 560. so times it by 4 you get 2,240 so he would need to sale about 28,000 to get 4240, but it a little over, so the answer to get $4000 is not perfect but the closest is $25,004 which is 7,000/100=70 x 3.5715 which will be $2,000.04.
Upon slight rearranging:
5xy-15y-40x+120, now factor 1st and 2nd pair of terms
5y(x-3)-40(x-3) which is equal to:
(5y-40)(x-3) if we factor the first parenthetical term as well
5(y-8)(x-3)
So (y-8) is a factor
It may be observed from the given that the probability of the both Samantha and Judith scoring an A is the product of the individual probabilities of Samantha and Judith. This means that the events are independent. Thus, the answer is letter A.
