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3 years ago

15

LaTasha paid $75 to joina summer gold program. The course where she plays charges $30 per round. Since she is a student, she rec

eives a $10 discount per round. If LaTasha spent $375, use the equation 375 = 20g + 75 to find how many rounds of gold LaTasha played.

2 answers:

GREYUIT [131]3 years ago

6 0

375=20g+75

-75 -75

300 = 20g

300/20 20g/20

g=15

sveticcg [70]3 years ago

4 0

She played 15 rounds. 375 -75 = 300. 300÷20=15

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bearhunter [10]

612.4285714285714 is the answer

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The common difference in an arithmetic sequence is –2 and the first term is 47. What is the 29th term?

BlackZzzverrR [31]

An arithmetic sequence is an ordered list of numbers where the next number is found by adding on to the last number (ex: 2,5,8,11... is a sequence where 3 is added on to find the next number).

The equation for an arithmetic sequence is
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$A_{n}$ is the "n-th" number in the sequence (ex: is the first term in the sequence)
d is the number you add (common difference) to find the next number
The first number in the sequence is 47 so $A_{1}=47$
<span>d=-2 because the question gives you that
</span>
$A_{n}=A_{1}+(n-1)d$
<span> $A_{29}=47+(29-1)(-2)$
</span><span> $A_{29}=47+(28)(-2)$
</span><span> $A_{29}=47+-56$
</span><span> $A_{29}=-9$
</span>
The answer is A. -9.

<u> </u>

<span>The answer is C. 158</span>

For the second one, it gives you $A_{1}=4$ and <span> $A_{}=18$
You can use this to find d

</span><span> $A_{n}=A_{1}+(n-1)d$
</span><span> $A_{3}=4+(3-1)d$
</span><span> $18=4+(3-1)d$
</span><span> $18=4+2d$
</span><span> $14=2d$
</span><span> $7=d$
</span>
Now you can just solve using the equation normally.
<span> $A_{n}=A_{1}+(n-1)d$
</span><span> $A_{23}=4+(23-1)(7)$
</span><span> $A_{23}=4+(22)(7)$
</span><span> $A_{23}=4+154$
</span><span> $A_{23}=158$
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The answer is C. 158

8 0

3 years ago

Read 2 more answers

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dedylja [7]

Answer:

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Step-by-step explanation:

<em>AD is enlarged to JM</em>

<em>AD² = 2² + 1² = 4 + 1 =5</em>

<em>AD = √5</em>

then you plug in JM

<em>JM² = 6² + 3² = 36 + 9 = 45</em>

<em>JM = √45 = 3 √5</em>

<em>so if </em>

<em>JM=3 AD</em>

then

<em>ML= 3 DC </em>

<em>then you add</em>

<em>5+3=8</em>

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2 years ago

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Reptile [31]

Answer:

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so we get

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then the it's will be

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which is

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finally we get

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2 years ago

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BARSIC [14]

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This problem can be expressed in a ratio:
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3 years ago