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WINSTONCH [101]
3 years ago
15

I need help with this question will mark brainliest

Mathematics
2 answers:
fomenos3 years ago
8 0
The last one is the answer
Anon25 [30]3 years ago
6 0
I think it’s D aka the last one
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Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0
3 years ago
Round off - 126,945 to the nearest hundred thousand nearest ten thousand nearest thousand which of these rounds amount to the cl
VARVARA [1.3K]
100,000 30,000 7,000

the first one i believe
5 0
3 years ago
Hi!! Can you pls help thanks:)
Pani-rosa [81]
1. Y=X-4
2. Y=X*4
3. Y=X+3
4. Y=X/6
8 0
3 years ago
Is the line through points p(-7,8) and q(-5,-6) parallel to the line throuh points R(3,-5) and S(-2,0)? explain.
BARSIC [14]
I'm going to use the slope formula which is
m = (y2 - y1)/(x2 - x1)
where (x1,y1) and (x2,y2) are the two points the line goes through

Slope of line PQ
m = (y2 - y1)/(x2 - x1)
m = (-6 - 8)/(-5 - (-7))
m = (-6 - 8)/(-5 + 7)
m = (-14)/(2)
m = -7
The slope of line PQ is -7

Slope of RS
m = (y2 - y1)/(x2 - x1)
m = (0 - (-5))/(-2 - 3)
m = (0 + 5)/(-2 - 3)
m = (5)/(-5)
m = -1
The slope of line RS is -1

Because the slopes are NOT equal (one is -7 and the other is -1), this means the lines are NOT parallel.

-----------------------------------------------------------------------------------------------------

Answer: Choice B) No, the lines have unequal slopes

5 0
3 years ago
Read 2 more answers
4x+23=9x-38 21y-1 value of y
PSYCHO15rus [73]

Answer:

4⅗.78 99⁹7./⅜87.5⅞8 /7 ⁰

5 0
3 years ago
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