Given that in a trianlgle the sides AB, BC, CA are in the ratio 3:4:6.
Let AB = 3k, BC = 4k and CA = 6k.
Then perimeter =3k+4k+6k = 13k
M, N, K are mid points of the sides.
By mid point theorem MN = 3k/2, NK = 4k/2 and KM = 6k/2
Hence perimeter of MNK = 13k/2 =5.2 (given)
Solve for k
k=2(5.2)/13 = 0.8
Hence sides are
AB = 3k = 3(0.8) = 2.4 in
BC = 4k= 3.2 in
CA = 4.8 in
Where P = perimeter, L = length, W = width, and A = area:
A = LW
P = 2(LW)
Hope this helped! :)
Answer:
x=27
Step-by-step explanation:
1. x-2=25 so add 2 to both sides x=25+2
2. 25+2= 27 so, the answer is x=27 Can you make me Brainliest
The rule is plus four because every time you take your x value and add four it equals your y value.
Answer:
B false
Step-by-step explanation:
The Theorem states that for a right triangle,
a^2 + b^2 = c^2
where c is the hypotenuse and a and b are the two shorter sides.
So does our given lengths work? Let's see:
16^2+30^2=35^2
256+900=1225
1156=1225
1156≠1225
And as we can see, the two sides do not equal each other, so this means the sides do not make a right triangle.
