Answer:
29. 15.87%
30. 4.75%
31. 0.62%
32. probability cannot be calculated (0%)
Step-by-step explanation:
We have that the formula of the normal distribution is:
z = (x - m) / sd
where x is the value we are going to evaluate, m is the mean and sd is the standard deviation
x = 16 and m = 16.5
when sd = 0.5
z = (16 - 16.5) /0.5
z = -1
Now when looking in the z table, we have that the corresponding value is 0.1587, that is, the probability is 15.87%
when sd = 0.3
z = (16 - 16.5) /0.3
z = -1.67
Now when looking in the z table, we have that the corresponding value is 0.0475, that is, the probability is 4.75%
when sd = 0.2
z = (16 - 16.5) /0.2
z = -2.5
Now when looking in the z table, we have that the corresponding value is 0.0062, that is, the probability is 0.62%
when sd = 0
z = (16 - 16.5) / 0
z = infinity
probability cannot be calculated
This is how I would solve it, I would act as if there were 36 people in the class.
36÷6=6×5=30
30÷3=10×2=20
20/36=10/18=5/9
You could also try another number such as 24;
24×(5÷6)=20
20×(2/3)=13.3(3 repeating)
13.333/24=5/9
5/9 people have dogs.
Tell me if this helps.
My only guess is a^2 + b^2 = c^2
Answer:
a) 
b) 
Step-by-step explanation:
For this case we can use a linear model to solve the problem.
s) Create an equation to express the increase on the price tickets and the number of seats sold
number of seats, if w analyze the info given the number of seats after increase the price is given by
.
And let P the price for the ticket. So after the increase in ticket price the expression for the increase is P-200.
We have an additional info, for each increase of $3 the number of setas decrease 1. And the equation that gives to us the price change in terms of the increase of price is:

So then our linear equation is given by:

b) Over a certain period, the number of seats sold for this flight ranged between 90 and 115. What was the corresponding range of ticket prices?
So for this case we just need to replace the limits into the linear equation and see what we got:


So the corresponding range of ticket prices is:

I’m pretty sure it would be equilateral because all the sides are the same:)