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Annette [7]
2 years ago
12

4. Find the percent of decrease from 340 to 150. Round to the nearest tenth of a

Mathematics
2 answers:
kramer2 years ago
8 0

Answer:

52.9%

Step-by-step explanation:

Vaselesa [24]2 years ago
8 0

Answer:

C) 55.9%

Step-by-step explanation:

<h2><u>PERCENTAGE DECREASE</u></h2>

340 - 150 = 190

190/340 * 100

= <u>C. ) 55.9 %</u>

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Find the value of "k", given that one solution of the equation x2-kx+21=0 is 3
Ilia_Sergeevich [38]
Plug in 3 for x and solve for k.
(3)^2-3k+21=0
3k=9+21
3k=30
k=10
5 0
3 years ago
Solve for x.<br><br><br> A.90<br> B.100<br> C.135<br><br><br><br><br> HELP ME
ipn [44]

Answer:

its B

Step-by-step explanation:

5 0
2 years ago
Maya was given 24 math problems she finished 5/ 6 of them how many more does Maya still have to finish
Tems11 [23]
U can multiply 5/6 by 4 and u get 20/24.so she has 4 more questions left to finish Hope this helps:)
4 0
2 years ago
Read 2 more answers
The curves r1(t) = 4t, t2, t3 and r2(t) = sin(t), sin(5t), 2t intersect at the origin. find their angle of intersection, θ, corr
san4es73 [151]
First get the tangent vectors by differentiating r1 and r2 
r_1 '(t) = (4,2t,3t^2) \\  \\  r_2'(t) = (cos (t), 5 cos(5t), 2)
Evaluate at t=0
r_1' = (4,0,0) \\  \\ r_2' = (1,5,2)

Use identity for angle between 2 vectors:
u*v = |u| |v| cos \theta

Evaluate dot product and unit vectors:
u*v = (4,0,0)*(1,5,2) = 4 \\  \\ |u| = \sqrt{4^2 +0^2+0^2} = 4 \\  \\ |v| = \sqrt{1^2 + 5^2+2^2} = \sqrt{30}

Sub into identity and solve for theta:
4 = 4 \sqrt{30} cos \theta \\  \\ cos\theta = \frac{1}{\sqrt{30}} \\  \\ \theta = 79.48

Answer:
Angle of intersection is about 79 degrees.




5 0
3 years ago
Please explain how to solve step by step. Thank you.
Brut [27]

3x-2 = 5x-14

Subtract 3x from each side:

-2 = 2x -14

Add 14 to each side:

12 = 2x

Divide both sides by 2:

x = 12/2

x = 6

4 0
2 years ago
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