Question

Figure GHTA below is a parallelogram. = 6 cm, = 8 cm, and the measure of = 60°. Find the area.

Answer 1

Answer:

multiply

Step-by-step explanation:

Answer 2

Answer:

The area of parallelogram GHTA is $41.568 cm^2$.

Step-by-step explanation:

Given parallelogram GHTA

GH = 8 cm =-AT

GA = 6 cm

∠ GAT =∠ GHT = 60°

To find = Area of parallelogram

Solution:

Draw perpendicular GO on the base AT.

In ΔGOA

$\sin 60^o=\frac{GO}{GA}=\frac{GO}{6 cm}$

(sin 60°=0.8660)

GO = 5.196 cm

Area of the parallelogram: GO × AT

$=5.196 cm\times 8 cm =41.568 cm^2$

The area of parallelogram GHTA is $41.568 cm^2$.