Answer:
Step-by-step explanation:
Given that,
f(3) = 2
f'(3) = 5.
We want to estimate f(2.85)
The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".
At x = a, y = f(a) and the slope of the tangent line is f'(a).
So, in point slope form, the tangent line has equation
y − f(a) = f'(a)(x − a)
The linearization solves for y by adding f(a) to both sides
f(x) = f(a) + f'(a)(x − a).
Given that,
f(3) = 2,
f'(3) = 5
a = 3, we want to find f(2.85)
x = 2.85
Therefore,
f(x) = f(a) + f'(a)(x − a)
f(2.85) = 2 + 5(2.85 - 3)
f(2.85) = 2 + 5×-0.15
f(2.85) = 2 - 0.75
f(2.85) = 1.25
r= 9 because 45/5 is 9 and it works the same way for the rest of the problems.
Considering the unit circle, it is found that the sine is negative on the third and on the fourth quadrant.
<h3>What is the unit circle?</h3>
For an angle 
the unit circle is a circle with radius 1 containing the following set of points: 
.
Hence, from the above explanation, the sine is negative when y is negativem, which is on the third and on the fourth quadrant.
More can be learned about the unit circle at brainly.com/question/16852127
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