y=4x^2+5x-6y=4x2+5x−6
:
Given points are :
x = -2 0 4
y=f(x) = 0 -6 78
We have to model the parabola with the help of these points
Solution:
We consider a standard equation of parabola y= ax^2+bx+cy=ax2+bx+c
now, we put the points in the equation we get,
at (-2,0) is 4a-2b+c=0
at (0,-6) is c=-6
at (4,78) is 78= 16a+4b+c
now, solving these equation we get, a= 4 , b= 5 , c= -6
so the equation formed with these points is y=4x^2+5x-6y=4x2+5x−6
we can see this in the graph attached.
Step-by-step explanation:
Hope this helps!! :D
The red fish is 34 feet underwater... in otherwords -34
The blue fish is 21 feet underwater... -21
Answer: 10
Step-by-step explanation:
9 1/6 x 1 1/11
55/6 x 12/11
cross reduce
5/1 x 2/1
10
200/2 cause it's half so it equals 100, hope i helped