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lord [1]
3 years ago
8

A rollercoaster holds 45 people there are 387 people waiting to board the rollercoaster how many times will the rollercoaster ne

ed to run to give everyone
a ride
Mathematics
2 answers:
frozen [14]3 years ago
7 0
What you need to do here is divide. If it holds 45 and there are 387 (long, long line) waiting to get on, then you divide 387 by 45. You get 8.6 so about 9 times. 
Dimas [21]3 years ago
3 0
Okay so 387/45 is 8.6 but, it is impossible for s ride to go around 8.6 times the answer is nine
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x = 2

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Step-by-step explanation:

\left \{ {{0.4x + 0.3y = 1.7} \atop {0.7x - 0.2y = 0.8}} \right.

\left \{ {{2(0.4x + 0.3y) = 2 * 1.7} \atop {3(0.7x - 0.2y) = 3 * 0.8}} \right.

\left \{ {{0.8x + 0.6y = 3.4} \atop {2.1x - 0.6y) = 2.4}} \right.

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4 0
2 years ago
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Elan Coil [88]

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3 years ago
In an isosceles triangle two sides are equal. The third side is two less than twice the length of the two equal sides. The perim
pogonyaev

Answer:

The equal sides' length = 10

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Step-by-step explanation:

Let the two equal sides' length be "x"

Let the third side length be "y"

Third side (y) is 2 LESS THAN TWICE the equal side, so we can write:

y = 2x - 2

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x + x + y = 38

Replacing y with 2nd equation, we have:

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3 0
3 years ago
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