Bob is going to rent a truck for one day. There are two companies he can choose from, and they have the following prices.
1 answer:
m = the number of miles driven
Company A cost = 76
[they charge $76 for unlimited mileage, so they don't charge by the miles driven]
Company B cost = 0.70m + 55
[they charge an initial fee of $55 plus $0.70 per mile(m)]
For what mileages will Company A charge less than Company B?
Company A cost < Company B cost -----> 76 < 0.70m + 55
To solve for m, isolate/get the variable "m" by itself in the inequality:
76 < 0.70m + 55 Subtract 55 on both sides
76 - 55 < 0.70m + 55 - 55
21 < 0.70m Divide 0.70 on both sides to get "m" by itself
30 < m [m is any number greater than 30]
Company A will charge less than Company B for mileages over/greater than 30.
You might be interested in
9514 1404 393
Answer:
4) 6x
5) 2x +3
Step-by-step explanation:
We can work both these problems at once by finding an applicable rule.
where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.
This can be referred to as the <em>power rule</em>.
Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:
lim[h→0](f(x+h)-f(x))/h = 2ax +b
__
4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.
5. The gradient of x^2 +3x +1 is 2x +3.
__
If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.