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rjkz [21]
3 years ago
9

Bob is going to rent a truck for one day. There are two companies he can choose from, and they have the following prices.

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
8 0

m = the number of miles driven

Company A cost = 76    

[they charge $76 for unlimited mileage, so they don't charge by the miles driven]

Company B cost =  0.70m + 55  

[they charge an initial fee of $55 plus $0.70 per mile(m)]

For what mileages will Company A charge less than Company B?

Company A cost < Company B cost  ----->   76 < 0.70m + 55      

To solve for m, isolate/get the variable "m" by itself in the inequality:

76 < 0.70m + 55     Subtract 55 on both sides

76 - 55 < 0.70m + 55 - 55

21 < 0.70m     Divide 0.70 on both sides to get "m" by itself

\frac{21}{0.70}

30 < m      [m is any number greater than 30]

Company A will charge less than Company B for mileages over/greater than 30.

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Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. A = 56°, a = 12, b = 14
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We know that
case 1)
Applying the law of sines
a/Sin A=b/Sin B
A=56°
a=12
b=14
so
a*Sin B=b*Sin A----> Sin B=b*Sin A/a---> Sin B=14*Sin 56°/12
Sin B=0.9672
B=arc sin (0.9672)------> B=75.29°-----> B=75.3°

find angle C
A+B+C=180°-----> C=180-(A+B)----> C=180-(56+75.3)----> C=48.7°

find c
a/Sin A=c/Sin C----> c=a*Sin C/Sin A----> c=12*Sin 48.7°/Sin 56°)
c=10.87-----> c=10.9

the answer Part 1)
the dimensions of the triangle N 1
are
a=12  A=56°
b=14  B=75.3°
c=10.9  C=48.7°

case 2) 
A=56°
a=12
b=14
B=180-75.3----> B=104.7°

find angle C
A+B+C=180°-----> C=180-(A+B)----> C=180-(56+104.7)----> C=19.3°

find c
a/Sin A=c/Sin C----> c=a*Sin C/Sin A----> c=12*Sin 19.3°/Sin 56°)
c=4.78-----> c=4.8

the answer Part 2)
the dimensions of the triangle N 2
are
a=12  A=56°
b=14  B=104.7°
c=4.8    C=19.3°
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Answer:

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