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IgorLugansk [536]
3 years ago
6

Both Pythagorean Theorem and trigonometric ratios are used with right triangles. Explain what information you need to apply to t

hese different methods and include examples to show how to use each.
Mathematics
2 answers:
Reika [66]3 years ago
7 0
If given the value of an angle of the right triangle (aside from the 90° angle), then the trigonometric ratios will be more useful for solving for the sides of the triangle. One could use sin, cosin, and tangeant, the main trigonmetric ratios to solve for all sides and angles of the triangle, if given at least one angle and one side length. 

The Pythagorean Theorem as it is generally applied, helps solve for the third side of a triangle, given that you know the other 2 sides. This is less applicable, and trigonometric ratios can also be used in this case to solve for the rest of the triangle's angles and the third side. 
vovangra [49]3 years ago
4 0

Answer:

Step-by-step explanation:

“If given the value of an angle of the right triangle (aside from the 90° angle), then the trigonometric ratios will be more useful for solving for the sides of the triangle. One could use sin, cosin, and tangeant, the main trigonmetric ratios to solve for all sides and angles of the triangle, if given at least one angle and one side length. 

The Pythagorean Theorem as it is generally applied, helps solve for the third side of a triangle, given that you know the other 2 sides. This is less applicable, and trigonometric ratios can also be used in this case to solve for the rest of the triangle's angles and the third side. “.- pyton

Read more on Brainly.com - brainly.com/question/6241673#readmore

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\chi^2 =\frac{60-1}{64} 36 =33.19

The degrees of freedom are:

df= n-1= 60-1= 59

And the p value would be given by:

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Step-by-step explanation:

Data given

n=60 represent the sample size

\alpha=0.01 represent the confidence level  

s^2 =6^2 =36 represent the sample variance obtained

\sigma^2_0 =8^=64 represent the value that we want to test

Hypothesis to test

We want to verify if the true deviation is equal to 8 days o not, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 64

Alternative hypothesis: \sigma^2 \neq 64

The statistic is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

Replacing we got:

\chi^2 =\frac{60-1}{64} 36 =33.19

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And the p value would be given by:

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