Answer:
In parallelogram ABCD
FD is perpendicular to BC
BE is perpendicular to CD
Consider triangle BEC and triangle DFC
FC = EC (Given)
Angle BEC = Angle DFC (=90°)
Angle BCE = Angle DCF (common)
Therefore triangle BEC is congruent to triangle DFC (AAS congruency)
DF = BE (CPCT)
Since the altitudes are equal their bases will also be equal
Therefore BC = DC
Therefore BC = DC = AD = AB
Therefore ABCD is a rhombus
Hope this helps!
Mark me as brainliest
Step-by-step explanation:
Use the formula (Y2 - Y1)/(X2 - X1) to find the slope between two points
We'll make Point 1 (which is X1 and Y1) the Y-intercept so
X1, Y1 = (0, 5.00)
And we'll make Point 2 (which is X2 and Y2) the point on the trend line
X2, Y2 = (200, 6.00)
Plug into the formula:
(6.00 - 5.00)/(200 - 0)
= 1/200 or 0.005
Slope: 1/200 or 0.005
---
If this helps, please mark as Brainliest! :)
Answer:
(-5,7) (-5,8) (-5,3)
Step-by-step explanation:
Dont know if this will help but here you go
Answer:
I Have noidea
Step-by-step explanation:
sorry
