Answer:
see explaination
Step-by-step explanation:
Using the formulla that
sum of terms number of terms sample mean -
Gives the sample mean as \mu=17.954
Now varaince is given by
s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97
and the standard deviation is s=\sqrt{9.97}=3.16
b) The standard error is given by
\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45
c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1
Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88
d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05
Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96
or a number which is less than 15.83-1.5(4.05)=9.76
As there is no such number so the given sample has no outliers
I’m hoping this helps (but hopefully now you can give the brainliest to the person above)
I’m not very familiar with the square roots method but I believe you try and isolate the term that is squared.
Hola User_______________
Here IS YOUR Answer...!!!
_______________________
A.) 5.) 2/3 × 2/3 × 2/3 = (2/3)^3
6.) 4 × 4 × 4 = (4)^3
B.) 8.) (0.25) × (0.25) × (0.25)
9.) (1/9)×(1/9)×(1/9)
C.)
11.)3^3 = 9 and 4^3 = 64
12.)(4)^6 miles = 4096 miles
1.5483 repeating
Hope this helped :)
The formula is E= kQ/ d^2
k is 9x10^9
i changed 15 cm to 0.15 m
=> 9x10^9 x 12 OVER (0.15)^2
the answer is 4.8x10^12 N/C
but this is the electric field.
to find electric field STRENGTH, it’s E= F/q and you did not give a value for the force
