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2 years ago

Which values of P and Q does the following equation have infinitely many solutions?

Mathematics

1 answer:

vladimir1956 [14]2 years ago

4 0

Any value as long as P = Q

For the equation to have infinitely many solutions, we require both sides of the equation to have exactly the same terms.

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NEED HELP ASAP !!!!<br><br> Which graphs represents the compound inequality x≤ 5 orx≥ 5?

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Answer:

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John has 6/8 of pie left after a party. He bakes 1/6 times the pie. How many pie does he have now?

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The answer is 0.125 of a pie left

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How to write 8 17/20 as a decimal number

worty [1.4K]

Hello!

Answer:

In order to convert mixed number 8 17/20 to decimal form, you follow these steps:

Convert the proper fraction to a decimal: Divide the numerator by the denominator

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3 years ago

Really need help guys!<br> Love you if you can solve them wiz steps!!!!

Marta_Voda [28]

Answer:

Step-by-step explanation:

$x^2+y^2-8x+4y+4=0\\\\a)\\\\x^2-8x+y^2+4y+4=0\\\\x^2-2*x*4+(y^2+2*y*2+2^2)=0\\\\x^2-2*x*4+4^2+(y+2)^2=4^2\\\\(x-4)^2+(y+2)^2=4^2\\$

Hence,

The radius of the circle is 4 units, coordinates of its centre are (4,-2).

$b)\\\\y=0\\x^2+0^2-8x+4*0+4=0\\x^2-8x+4=0\\a=1\ \ \ \ b=-8\ \ \ \ c=4\\D=(-8)^2-4*1*4\\D=64-14\\D=48\\\sqrt{D}=\sqrt{48} \\ \sqrt{D}=\sqrt{16*3} \\\sqrt{D}=\sqrt{4^2*3} \\\sqrt{D}=4\sqrt{3} \\\displaystyle\\x=\frac{-(-8)б4\sqrt{3} }{2*1} \\\\x=\frac{8б4\sqrt{3} }{2} \\x_1=4-2\sqrt{3} \\x_2=4+2\sqrt{3}$

$c)\\\\A(6,2\sqrt{3}-2)\\ (x-4)^2+(y+2)^2=4^2\\(6-4)^2+(2\sqrt{3} -2+2)^2=16\\2^2+(2\sqrt{3} )^2=16\\4+2^2*(\sqrt{3})^2=16\\ 4+4*3=16\\4+12=16\\16\equiv16$

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