Answer:
1) is not possible
2) P(A∪B) = 0.7
3) 1- P(A∪B) =0.3
4) a) C=A∩B' and P(C)= 0.3
b) P(D)= 0.4
Step-by-step explanation:
1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4 . Thus the maximum possible value of P(A∩B) is 0.4
2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by
P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7
P(A∪B) = 0.7
3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3
4) the event C that the selected student has a visa card but not a MasterCard is given by C=A∩B' , where B' is the complement of B. Then
P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3
the probability for the event D=a student has exactly one of the cards is
P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4
Answer:
x=-6
Step-by-step explanation:
Follow along:
1. Distribute the -3 to those within the parenthesis.
-3x-6=12
2. Move the whole numbers to one sides, isolate the variable.
-3x=18
3. Divide both sides by -3
x=-6
Answer:
Step-by-step explanation:
12: 8,700
13: 42
14: 70,000
15: 5,000,000,000
16: 2,210
17: 34,100
18: 1,650
19: 149
20: 290,000
3*2*6 is 36 yards cubed or 36 yards to the power of 3.
Answer:
hi thanks
Step-by-step explanation:
