All categories

3 years ago

Find an equation of the line passing through the pair of points. Write the equation in the form Ax+By=C

Mathematics

1 answer:

dexar [7]3 years ago

8 0

-5x+y=-7 is the answer for this problem

You might be interested in

Describe the motion of a particle with position (x, y) as t varies in the given interval. (For each answer, enter an ordered pai

DerKrebs [107]

Answer:

The motion of the particle describes an ellipse.

Step-by-step explanation:

The characteristics of the motion of the particle is derived by eliminating $t$ in the parametric expressions. Since both expressions are based on trigonometric functions, we proceed to use the following trigonometric identity:

$\cos^{2} t + \sin^{2} t = 1$ (1)

Where:

$\cos t = \frac{y-3}{2}$ (2)

$\sin t = x - 1$ (3)

By (2) and (3) in (1):

$\left(\frac{y-3}{2} \right)^{2} + (x-1)^{2} = 1$

$\frac{(x-1)^{2}}{1}+\frac{(y-3)^{2}}{4} = 1$ (4)

The motion of the particle describes an ellipse.

7 0

3 years ago

A parabola and it’s directrix are shown on the graph. What are the coordinates of the focus of the parabola?

Svetllana [295]

Answer:

a. (0,2)

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

a drawer contains 9 white paper clips, 5 green paper clips, and 6 red paper clips. One paper clip is selected at random. What is

tatyana61 [14]

Answer:

the answer should be 9/14

Step-by-step explanation:

you add them all up then subtract the red for your denominator

then just put the number of white on top for your numerator

6 0

3 years ago

Read 2 more answers

I need the answer for this exact question

denis23 [38]

Answer:

$y=\frac{7}{2}x-20$

Step-by-step explanation:

Let the equation of the line be $y-y_1=m(x-x_1)$ where, 'm' is its slope and $(x_1,y_1)$ is a point on it.

Given:

The equation of a known line is:

$y=-\frac{2}{7}x+9$

A point on the unknown line is:

$(x_1,y_1)=(4,-6)$

Both the lines are perpendicular to each other.

Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is $m_1=-\frac{2}{7}$

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

$m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}$

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

$y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20$

The equation of a line perpendicular to the given line and passing through (4, -6) is $y=\frac{7}{2}x-20$ .

3 0

3 years ago

-9f +19-1 + f) 12-=8f <br>is this the answer?

jeka94

Hi!

-9f + 19 - 1 + f is actually -8f + 18.

To do this we add like terms, -9f and f; and 19 and -1

-9f + f is -8f

19 - 1 is 18

Therefore your answer is -8f + 18

7 0

2 years ago