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seropon [69]
3 years ago
9

A hyperbola in the form (x ^ 2)/(a ^ 2) - (y ^ 2)/(b ^ 2) = 1 has a center, vertices, and foci that fall along a horizontal. Ple

ase select the best answer from the choices provided. True or false

Mathematics
1 answer:
Lyrx [107]3 years ago
6 0

Answer:

True

Step-by-step explanation:

<u><em>Explanation</em></u>:-

The equation of the standard hyperbola is  

                         \frac{x^{2} }{a^{2} } - \frac{y^{2} }{b^{2} } =1

  •       Center is (0,0)
  • Hyperbola is symmetric with respective to both the axes, since if (x, y) is a point on the hyperbola, then (-x, y), (-x,-y), (x,-y) are also lie on the parabola.
  • The relation of between focus and transverse and conjugate axes c²=a²+b²
  • The transverse axis is along x-axis  
  • The conjugate axis  is along y-axis
  • The length of transverse axis is 2 a
  • The length of conjugate axis is 2 b
  • The foci is (±c,0) and the equation of foci is x=±a e)
  • The length of Latus rectum is \frac{2b^{2} }{a}

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Julli [10]

1 Move all terms to one side.

{x}^{2}+15x+45=0

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2 Use the Quadratic Formula.

x=\frac{-15+3\sqrt{5}}{2},\frac{-15-3\sqrt{5}}{2}

x=

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6 0
3 years ago
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Determine the number of possible triangles, ABC, that can be formed given A = 30°, a = 4, and b = 10.
sweet [91]

Answer:

None

Step-by-step explanation:

We are given a triangle ABC with ∠A = 30°, sides a = 4 and b = 10.

According to the 'Law of Sines- Ambiguous Case', we have,

If a < b×sinA, then no triangle is possible.

If a = b×sinA, only one triangle is possible

If a > b×sinA, two triangles are possible.

So, we have,

b×sinA = 10 × sin30 = 10 × 0.5 = 5.

Now, as

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We get, according to the rule, no triangle is possible.

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3 years ago
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natulia [17]

Answer:

Option D doesn't make any sense.

Step-by-step explanation:

D) 7 hours of sleep correspond to an age of 19 years.

That is wrong.

If we use the expression provided

hours = 8 + 0.5*(18 -age)

hours = 8 + 0.5*(18 -19)

hours = 8 + 0.5*(-1)

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3 years ago
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Answer:

I likr=e the Story 12

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I really like how they jump and 1+1=2 right or is it 3???

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D^2y/dx^2+4dy/dx-12y=cos2x
rjkz [21]
If you're solving for x, you'd move all the terms containing x to the left side of the equation:

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