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3 years ago

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Piper claims that 3(2a + 2) is equivalent to 5a + 6. She checks her claim by substituting -3 for a. Is Piper's claim correct? Wh

y or Why not?
Please Help SOS!!!

1 answer:

Natali5045456 [20]3 years ago

4 0

Answer:

Piper's claim that 3(2a+2) is equal to 5a +6 is incorrect.

Step-by-step explanation:

The first step is to use the distributive property to distribute the 3 to BOTH the 2a and 2. The resulting expression is 6a+6 NOT 5a+6. Piper's mistake was most probably that she added 3 and 2 to get 5 instead of multiplying them together to get 6.

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Y= -x^2+2x+1 <br>i need help understanding

Eddi Din [679]

Answer:

Does not factor; domain = -∞<x<∞, range = f(x) ≤ 2.

Step-by-step explanation:

Assuming your end goal is to factor the polynomial

$y=-x^{2} +2x+1$

If we use the guess and check method we can see that there is no way to factor this polynomial.

However, if you are looking for a domain and range we can graph it on a graphing calculator. Just by looking at the graph, we can see that the domain is all real numbers, or -∞<x<∞, and the range is f(x) ≤ 2.

I hope this helped!

7 0

3 years ago

Which series of transformations will not map figure H onto itself

7nadin3 [17]

Answer:

D

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation $(x+0,y-2)$ will map vertices of the square into points

$(2,1)\rightarrow (2,-1);$
$(1,2)\rightarrow (1,0);$
$(2,3)\rightarrow (2,1);$
$(3,2)\rightarrow (3,0).$

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

$(2,-1)\rightarrow (2,3);$
$(1,0)\rightarrow (1,2);$
$(2,1)\rightarrow (2,1);$
$(3,0)\rightarrow (3,2)$

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation $(x+2,y-0)$ will map vertices of the square into points

$(2,1)\rightarrow (4,1);$
$(1,2)\rightarrow (3,2);$
$(2,3)\rightarrow (4,3);$
$(3,2)\rightarrow (5,2).$

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

$(4,1)\rightarrow (2,1);$
$(3,2)\rightarrow (3,2);$
$(4,3)\rightarrow (2,3);$
$(5,2)\rightarrow (1,2)$

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation $(x+3,y+3)$ will map vertices of the square into points

$(2,1)\rightarrow (5,4);$
$(1,2)\rightarrow (4,5);$
$(2,3)\rightarrow (5,6);$
$(3,2)\rightarrow (6,5).$

2nd transformation = reflection over y = -x + 7 will map vertices into points

$(5,4)\rightarrow (3,2);$
$(4,5)\rightarrow (2,3);$
$(5,6)\rightarrow (1,2);$
$(6,5)\rightarrow (2,1)$

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation $(x-3,y-3)$ will map vertices of the square into points

$(2,1)\rightarrow (-1,-2);$
$(1,2)\rightarrow (-2,-1);$
$(2,3)\rightarrow (-1,0);$
$(3,2)\rightarrow (0,-1).$

2nd transformation = reflection over y = -x + 2 will map vertices into points

$(-1,-2)\rightarrow (4,3);$
$(-2,-1)\rightarrow (3,4);$
$(-1,0)\rightarrow (2,3);$
$(0,-1)\rightarrow (3,2)$

These points are not the vertices of the initial square.

5 0

3 years ago

Can u answer with steps?

nasty-shy [4]

Answer:

if a:c=2:3 andb:c=3:4therefore a:c=2:4

8 0

2 years ago

Write the word sentence as an equation. Then solve the equation.

Zarrin [17]

Answer:

c = -7

Step-by-step explanation:

c + 10 = 3

subtract 10 on both sides of the equal sign

c = -7

8 0

3 years ago

1 × 100000 3x 10000 9 ×1000 8×100 5x 10 2 × 1 in standard form and word form

Ilya [14]

139852
one hundred thirty nine thousands eight hundred fifty two

5 0

3 years ago