For this case we first write the equation of which we will use:
I (db) = 10log (l / l)
We substitute the value of l.
We have then:
l = 10 ^ 8lo
Substituting in the given equation:
I (db) = 10log ((10 ^ 8lo) / lo)
Rewriting:
I (db) = 10 * log (10 ^ 8)
I (db) = 80
Answer:
I (db) = 80
option 4
Answer:C (-2, 1)
Step-by-step explanation:
A) distributive is where it distributes a number through a set of parenthesis.
Answer:
z= 0.375 or 3/8
Step-by-step explanation:
Answer:
Step-by-step explanation:
since there are 205 calories in 5 crackers we can represent this as
205/5
we need to find how many calories are in one cracker, so lets take "x" as the # of calories in 1 cracker
so

cross multiply
5x=205
divide by 5 on both sides
x=41
41 calories in 1 cracker
Number line: