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3 years ago

The sum of a + b is an odd number if

Mathematics

1 answer:

Grace [21]3 years ago

8 0

Answer:

a is an even number and b is an odd number

Step-by-step explanation:

if a is even and b is even then the sum would be even ex.10+6=16. I'd a and b are both odd the sum would be even ex. 13+9=22. one has to be odd and one has to be even for the sum to be odd ex. 5+4=9

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Solve and show your work for each question. What is 0.(24) ̅ ̅ expressed as a fraction in simplest form? What is 0.24 ̅ expresse

Elden [556K]

The answer to this question is 24/99. 0.24 with 24 repeating in fractional form is 24/99. You put a 9 in the denominator for every repeating digit.

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3 years ago

On a map, 2 inches represents an actual distance of 64 miles. Towns A and B are 608 miles apart. Find the distance between the t

Lelu [443]

Answer: The distance in the map is 19 inches.

Step-by-step explanation:

On the map. 2 inches represent an actual distance of 64 miles.

The actual distance between town A and town B is equal to 608 miles, we need to divide this distance into groups of 64 miles.

N = 608/64 = 9.5

And each one of those 9.5 groups is represented with 2 inches in the map, then the distance in the map is:

d = 9.5*2 inches = 19 inches.

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3 years ago

Read 2 more answers

For better clarification I guess

marissa [1.9K]

Answer:

1.) $=\frac{\sqrt{3}}{3}$

2.) $42\sqrt{30}$

Step-by-step explanation:

1.) $\mathrm{Multiply\:by\:the\:conjugate}\:\frac{\sqrt{3}}{\sqrt{3}}$

2.) $\mathrm{Apply\:radical\:rule}:\quad \sqrt{a}\sqrt{b}=\sqrt{a\cdot b}$

$\sqrt{6}\sqrt{5}=\sqrt{6\cdot \:5}$

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3 years ago

Write the number shown on the calculator display in standard form.

frez [133]

Answer:

2 Because visual specialization skills are important to success in so many career

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continue to improve your visualization skills?

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Step-by-step explanation:

2 Because visual specialization skills are important to success in so many career

fields, it is helpful to continue to build skill. What is one strategy you can use to

continue to improve your visualization skills?

Please someone help!!!

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3 years ago

3. The curve C with equation y=f(x) is such that, dy/dx = 3x^2 + 4x +k

Andreas93 [3]

a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

$\displaystyle \frac{dy}{dx} = 3x^2 + 4x + k \implies y = f(0) + \int_0^x (3t^2+4t+k) \, dt$

Evaluate the integral to solve for y :

$\displaystyle y = -2 + \int_0^x (3t^2+4t+k) \, dt$

$\displaystyle y = -2 + (t^3+2t^2+kt)\bigg|_0^x$

$\displaystyle y = x^3+2x^2+kx - 2$

Use the other known value, f(2) = 18, to solve for k :

$18 = 2^3 + 2\times2^2+2k - 2 \implies \boxed{k = 2}$

Then the curve C has equation

$\boxed{y = x^3 + 2x^2 + 2x - 2}$

b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:

$\dfrac{dy}{dx}\bigg|_{x=a} = 3a^2 + 4a + 2$

The slope of the given tangent line $y=x-2$ is 1. Solve for a :

$3a^2 + 4a + 2 = 1 \implies 3a^2 + 4a + 1 = (3a+1)(a+1)=0 \implies a = -\dfrac13 \text{ or }a = -1$

so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).

Decide which of these points is correct:

$x - 2 = x^3 + 2x^2 + 2x - 2 \implies x^3 + 2x^2 + x = x(x+1)^2=0 \implies x=0 \text{ or } x = -1$

So, the point of contact between the tangent line and C is (-1, -3).

7 0

2 years ago