Answer:
About 6 athletes.
Step-by-step explanation:
We are concerned only with the percent of athletes that are above one standard deviation.
Between one standard deviation and two standard deviations, there is 13.6% of the athletes.
From 2 to 3, there is 2.1%. Above 3, there is 0.2%.
The sum of those percentages is 15.9% of 40 = 0.159 · 40 = 6.36 or about 6 athletes.
Hope this helps.
if she bought the shirts you have to double 3:50 which equals $7 so double 7 it is 14. So Dave spend half that amount which would be 3:50
Answer:
p=4
Step-by-step explanation:
4p-3=13
4p=3+13
4p=16
p=4
Answer:
yes
Step-by-step explanation:
You can perform the "line test." If it is a function, there will not be two x's of the same value. In this case, x is 2,6,-1. No number repeats, thus making a function.
Number of weekend minutes used: x
Number of weekday minutes used: y
This month Nick was billed for 643 minutes:
(1) x+y=643
The charge for these minutes was $35.44
Telephone company charges $0.04 per minute for weekend calls (x)
and $0.08 per minute for calls made on weekdays (y)
(2) 0.04x+0.08y=35.44
We have a system of 2 equations and 2 unkowns:
(1) x+y=643
(2) 0.04x+0.08y=35.44
Using the method of substitution
Isolating x from the first equation:
(1) x+y-y=643-y
(3) x=643-y
Replacing x by 643-y in the second equation
(2) 0.04x+0.08y=35.44
0.04(643-y)+0.08y=35.44
25.72-0.04y+0.08y=35.44
0.04y+25.72=35.44
Solving for y:
0.04y+25.72-25.72=35.44-25.72
0.04y=9.72
Dividing both sides of the equation by 0.04:
0.04y/0.04=9.72/0.04
y=243
Replacing y by 243 in the equation (3)
(3) x=643-y
x=643-243
x=400
Answers:
The number of weekends minutes used was 400
The number of weekdays minutes used was 243
