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2 years ago

Algebra is my bane...

Mathematics

1 answer:

katovenus [111]2 years ago

4 0

Answer:

The answer is D

Step-by-step explanation:

The answer is D

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A regular hexagon is dilated by a scale factor of 2.5. What happens to the perimeter in this process?

Savatey [412]

Answer:

Step-by-step explanation:

perimeter of larger hexagon=2.5 perimeter of smaller hexagon

8 0

2 years ago

Multiply. (2x2 + 4x - 3)(x2 - 2x + 5)

BigorU [14]

For a moment, let $y=x^2-2x+5$ . Then by the distributive property,

$(2x^2+4x-3)p=2x^2p+4xp-3p$

Again by the distributive property,

$2x^2p=2x^2(x^2-2x+5)=2x^4-4x^3+10x^2$

$4xp=4x(x^2-2x+5)=4x^3-8x^2+20x$

$-3p=-3(x^2-2x+5)=-3x^2+6x-15$

Taking everything together, we get

$(2x^2+4x-3)(x^2-2x+5)=(2x^4-4x^3+10x^2)+(4x^3-8x^2+20x)+(-3x^2+6x-15)$
$(2x^2+4x-3)(x^2-2x+5)=2x^4-x^2+26x-15$

7 0

3 years ago

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Can someone help it’s due in 40mins!!

Lorico [155]

Answer:

Step-by-step explanation:

$\frac{8}{32} = \frac{4}{16} = \frac{2}{8} = \frac{1}{4}$

$\frac{27}{54} = \frac{9 }{18} = \frac{3}{6} = \frac{1}{2}$

$\frac{36}{24} = \frac{18}{12} = \frac{9}{6} = \frac{3}{2}$

$\frac{30}{60} = \frac{15}{30} = \frac{5}{10} = \frac{1}{2}$

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2 years ago

Which equation is equivalent to

Alexeev081 [22]

It y=4z-3/6 BOOMM done for ya

7 0

3 years ago

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Which part of the graph best represents the solution set to the system of inequalities y<_ x+1 and y+x<_ -1

Pavel [41]

Hello!

Remember that the symbols: ≤ and ≥ are graphed as a solid line. While the symbols: < and > are graphed as a dotted line.

Also, before graphing, it would be better to convert both equations to slope-intercept form.

y ≤ x + 1 is already in slope-intercept form.

y + x ≤ -1 is not written in slope-intercept form. (Slope-intercept form: y = mx + b)

y + x ≤ - 1 (subtract x from both sides)

y ≤ -x - 1

Graphing those lines, you get the graph below. You can see that Part C best represents the solution set systems of inequalities, because that is where both of the shaded lines intersect.

Answer: Part C

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2 years ago

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