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katrin [286]
3 years ago
8

I am not too sure if I got this right. Can someone double check for me? Will mark brainly.

Mathematics
1 answer:
Vadim26 [7]3 years ago
5 0

Answer:

you are correct

Step-by-step explanation:

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6 0
3 years ago
Solve.
Eva8 [605]

2x^2+x-1=2\ \ \ |-2\\\\2x^2+x-3=0\\\\2x^2+3x-2x-3=0\\\\x(2x+3)-1(2x+3)=0\\\\(2x+3)(x-1)=0\iff 2x+3=0\ \vee\ x-1=0\\\\2x+3=0\ \ |-3\\2x=-3\ \ \ |:2\\x=-\frac{3}{2}\\\\x-1=0\ \ \ |+1\\x=1

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