Nelson decides to invest $1,000,000 in a period annuity that

Answer:

4√10

Step-by-step explanation:

Hello!

Let's first simplify the radical.

We can do this by expanding the radical:

We need to pull out a perfect square factor to expand a radical and simplify it. In 45, we have 9 and 5 multiplied, and 9 is a perfect square.

Let's work with √45:

√45 can be written as √9 * √5 (using the rule √ab = √a * √b)
√9 simplifies to 3, so it is 3√5

Now we can simplify the operation in the parenthesis by combining like terms:

3√5 + √5
√5 + √5 + √5 + √5
4√5

Now using the same rule as above, we can multiply the values:

√2(4√5)
4√10

Your solution is 4√10

3 0

2 years ago

Janelle is selling lemonade. she has poured 36 cups of lemonade to display. draw one possible array janelle could use to display

aleksklad [387]

She could create 6 rows with 6 columns to display the cups.

5 0

3 years ago

Read 2 more answers

On a car trip, Ben drove 65 miles more than half the number of miles Steve drove. Together they drove 500 miles. How many miles

tatyana61 [14]

Answer:

210 miles

Step-by-step explanation:

Let's represent it mathematically.

Ben drove 65 miles more than half the number of miles Steve drove, so we represent it by

B = 65 + ½S

It is also said that together, they drove 500 miles, we represent it with.

B + S = 500

Now, we solve simultaneously.

Let's eliminate the ½ in Ben's drive. So we multiply the equation by 2.

2B = 130 + S.

Rearranging, we have

S = 2B - 130.

We substitute this value of S, in the second equation. So we have.

B + (2B - 130) = 500, open the brackets

B + 2B - 130 = 500

3B - 130 = 500, collecting the like terms

3B = 500 + 130

3B = 630

B = 630/3

B = 210 miles.

Therefore, Ben drove 210 miles.

Kindly vote Brainliest.

7 0

3 years ago

The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 43 o

xeze [42]

Answer:

a) 95% of the widget weights lie between 29 and 57 ounces.

b) What percentage of the widget weights lie between 12 and 57 ounces? about 97.5%

c) What percentage of the widget weights lie above 30? about 97.5%

Step-by-step explanation:

The empirical rule for a mean of 43 and a standard deviation of 7 is shown below.

a) 29 represents two standard deviations below the mean, and 57 represents two standard deviations above the mean, so, 95% of the widget weights lie between 29 and 57 ounces.

b) 22 represents three standard deviations below the mean, and the percentage of the widget weights below 22 is only 0.15%. We can say that the percentage of widget weights below 12 is about 0. Equivalently we can say that the percentage of widget weights between 12 an 43 is about 50% and the percentage of widget weights between 43 and 57 is 47.5%. Therefore, the percentage of the widget weights that lie between 12 and 57 ounces is about 97.5%

c) The percentage of widget weights that lie above 29 is 47.5% + 50% = 97.5%. We can consider that the percentage of the widget weights that lie above 30 is about 97.5%

3 0

3 years ago

Twelve times one-half of a number is thirty <br> six. What is the number? a. 3 b. 6 C. 8 d. 18

sukhopar [10]

The number would be C- 6

7 0

3 years ago