Suppose the length of the vegetable garden is increased by 50%. The new length can be written as (3y + 5) + 1 2(3y + 5) or 1.5(3
1 answer:
Answer:
Given:
Length of the garden is represented by :
The length is increased by 50%.
To find the new length.
Solution:
1) The original length =
The increase in length will be = of
⇒
⇒
The new length = <em>Original length + Increased length </em>=
2) Let the original length = 100%
Increase percent of length = 50%
Total percent of length =
New length = of
⇒
⇒
Thus, the new length of the garden can be represented by both expression :
or
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Answer:
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Step-by-step explanation:
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Answer:
Match each of the trigonometric expressions below with theequivalent non-trigonometric function from the following list.Enter the appropiate letter(A,B, C, D or E)in each blank
A . tan(arcsin(x/8))
B . cos (arsin (x/8))
C. (1/2)sin (2arcsin (x/8))
D . sin ( arctan (x/8))
E. cos (arctan (x/8))
These are the spaces to fill out :
.. ..........x/64 (sqrt(64-x^2))
.............x/sqrt(64+x^2)
.............sqrt(64-x^2)/8
..............x/sqrt(64-x^2)
..............8/sqrt(64+x^2)
A. ........tan(arcsin(x/8)) =......x/sqrt(64-x^2)
B . cos (arsin (x/8)) ....sqrt(64-x^2)/8
Step-by-step explanation:
To solve this we have to find the missing sides to each of the triange discribed in prenthesis thus
A we have the sides of the triangle given by x, 8 and or
thus tan(arcsin(x/8)) = =
Therefore ........tan(arcsin(x/8)) =......x/sqrt(64-x^2)
B
Here we have cos = adjacent/hypotenuse where adjacent side is and hypothenuse = 8 we have
/8
B . cos (arsin (x/8)) ....sqrt(64-x^2)/8
