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Bond [772]
3 years ago
8

ASAP Use elimination -2x+5y=-20 2x-2y=20

Mathematics
2 answers:
poizon [28]3 years ago
7 0

Answer:

the answer is x=10 and y=0

Step-by-step explanation:

Inga [223]3 years ago
3 0

Answer:

X=10, Y=0

Step-by-step explanation:

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Which is the real world situation that can be described by a linear inequality
garik1379 [7]

Answer:

Pretty sure it's B

Step-by-step explanation:

Everything else would be more like an equation. I think B is the only inequality.

7 0
3 years ago
Using division to find ratios that are equivalent to 40:28
GrogVix [38]

Answer: 10:7

Step-by-step explanation:

40:28=10*7

6 0
3 years ago
A Ferris wheel has a diameter of 56 ft. how far will a rider travel during a 4-minute ride if the wheel rotates once every 20 se
Luba_88 [7]
First calculate the circumference. Usually this is the diameter times pi, but since we are told to estimate pi, the circumference equals 56 * 22/7 or 176 feet.
In 4 minutes, 4 * 60 = 240 seconds pass. In this time, a 20 second period will occur 240/20 = 12 times.
So we know that the rider rotates 12 times and each rotation takes them 176 feet, meaning that they will travel 12 * 176 =  2112 feet
5 0
3 years ago
Sam plans to walk his dog a distance of a mileHe walks 3/8 of a mile and stop and get a bottle of waterThen he walks 1/8 of a mi
DedPeter [7]

Answer:

1/2 mile

Step-by-step explanation:

3/8+1/8=4/8 or 1/2 simplified

1-1/2=1/2

same has to walk 1/2 mile more to walk his dog a full mile

3 0
3 years ago
A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.
irakobra [83]

Answer:

The integral is equal to 5\sec^2(2x)+C for an arbitrary constant C.

Step-by-step explanation:

a) If u=\tan(2x) then du=2\sec^2(2x)dx so the integral becomes \int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C. (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case u=\sec(2x) hence du=2\tan(2x)\sec(2x)dx. We rewrite the integral as \int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C.

c) We use the trigonometric identity \tan(2x)^2+1=\sec(2x)^2 is part b). The value of the integral is 5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C. which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.  

3 0
3 years ago
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