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SpyIntel [72]
4 years ago
6

4 15/16+7 3/4 simplest form

Mathematics
2 answers:
stealth61 [152]4 years ago
8 0
the answer is 203/16 or 12.6875
Svetlanka [38]4 years ago
4 0
Hey,here is the Answer to your question...!!!
4 15/16+7 3/4
=>79/16+31/4
=>79+124/16=203/16...
Hope this helps u...!!!
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erastovalidia [21]

Answer:

linear

Step-by-step explanation:

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3 years ago
Express the null hypothesis and the alternative hypothesis in symbolic form. Use the correct symbol ( μ, rho, σ) for the indicat
ipn [44]

Answer:

c) H0 : p = 5.8%

H1 : p > 5.8%

Step-by-step explanation:

At the null hypothesis, we test that the percentage is equal to a certain value. At the alternate hypothesis, we have a test about this percentage, if it is more, less, or different from the tested value.

A psychologist claims that more than 5.8 percent of the population suffers from professional problems due to extreme shyness

At the null hypothesis, we test if the percentage is 5.8%

H_0: p = 5.8\%

At the alternate hypothesis, we test if this percentage is more than 5.8%. So

H_a: p > 5.8\%

This means that the correct answer is given by option c.

3 0
3 years ago
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Heeeeeelp plssssssss
victus00 [196]

Answer:

Your right?

Step-by-step explanation:

its the only answer that actually qualifies. Although any number above 20 would work I guess. there are no requirements.

4 0
3 years ago
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Use the similar triangles to find the slope on the lines??? Hello plzzz
ch4aika [34]

Answer:

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3 years ago
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Previously, an organization reported that teenagers spent 24.5 hours per week, on average, on the phone. The organization thinks
Lena [83]

Answer:

We need to develop a one-tail t-student test ( test to the right )

We reject H₀  we find evidence that student spent more than 24,5 hours on the phone

Step-by-step explanation:

Sample size  n = 15     n < 30

And we were asked if the mean is higher than, therefore is a one-tail t-student test ( test to the right )

Population mean   μ₀  = 24,5

Sample mean   μ  =  25,7

Sample standard deviation s = 2

Hypothesis Test:

Null Hypothesis      H₀                             μ  =  μ₀

Alternative Hypothesis     Hₐ                  μ  >  μ₀

t (c) =  ?

We will define CI = 95 %  then   α = 5 %   α = 0,05    α/2 =  0,025

n = 15     then degree of freedom    df = 14

From t-student table  we get:  t(c) = 2,1448

And  t(s)

t(s) = ( μ  -  μ₀  ) / s/√n

t(s) = (25,7 - 24,5) /2/√15

t(s) = 2,3237

Now we compare   t(c)   and  t(s)

t(c)  =  2,1448         t(s)  = 2,3237

t(s) > t(c)

Then we are in the rejection region we reject H₀   we have evidence at 95% of CI that students spend more than 24,5 hours per week on the phone

8 0
3 years ago
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