This answer would be (-14).
Answer: option D. 2x^2 + (3/2)x - 5
Explanation:
1) polynomials given:
f(x) = x/2 - 2 and g(x) = 2x^2 + x - 3
2) question: find (f + g) (x)
That means that f(x) + g(x), so you have to add up the two polynomials given.
3) x/2 - 2 + 2x^2 + x - 3
4) Combine like terms:
a) terms with x^2: you only have 2x^2, so it is not combined with other term.
b) terms with x: x/2 + x
that is a sum of fractions: x/2 + x = [x + 2x] / 2 = 3x / 2 = (3/2)x
c) constant terms: - 2 + (-3) = - 2 - 3 = - 5
5) Result: 2x^2 + (3/2)x - 5
That is the option d.
9514 1404 393
Answer:
see below
Step-by-step explanation:
It is easiest to compare the equations when they are written in the same form.
The first set can be written in slope-intercept form.
y = 2x +7
y = 2x +7 . . . . add 2x
These equations are <em>identical</em>, so have infinitely many solutions.
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The second set can be written in standard form.
y +4x = -5
y +4x = -10
These equations <em>differ only in their constant</em>, so have no solutions.
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The third set is already written in slope-intercept form. The equations have <em>different slopes</em>, so have exactly one solution.
7(12 1/3) + 8(12 1/3 + 1/4) = 3(6(12 1/3) - 9) - 8
12 1/3 = 12.33
1/4 = 0.25
7(12.33) + 8(12.33 + 0.25) = 3(6(12.33) - 9) - 8
86.31 + 8(12.58) = 3(73.98 - 9) - 8
86.31 + 100.64 = 3(64.98) - 8
186.95 = 186.94 - 8
186.95 ≠ 178.94
False. The x, when 12 1/3 does not work inside this equation
hope this helps