Answer:
<h3>The probability that atleast 2 of them come up heads is 0.5</h3><h3>∴ P(A)=0.5</h3>
Step-by-step explanation:
Given that three fair coins are flipped.
<h3>
To find the probability that at least 2 of them come up heads:</h3>
Sample space for the given event is
<h3>∴ n(S)=8</h3>
Let A be the events of getting atleast 2 Heads and is given by
A = {HHH, HHT, HTH, THH}
<h3>∴ n(A)=4</h3>
Probability of Getting atleast 2 Heads in 3 Coin Tosses is
<h3>∴ P(A)=0.5</h3><h3>∴ the probability that atleast 2 of them come up heads is 0.5</h3>
The answer is D.
y = 3x - 4
(5, 11)
11 = 3(5) - 4
11 = 15 - 4
11 = 11
(2, 2)
y = 3x - 4
2 = 3(2) - 4
2 = 6 - 4
2 = 2
SSS (side-side-side) requires that all three sides of the potentially congruent triangles be congruent.
Triangle WVU & Triangle UBW are our two triangles.
The middle line, UW and WU are congruent by the reflexive property, so that is not the information we need to prove SSS.
For SSS, we need to know that sides WV and UB are congruent.
Hope this helps!
So if I had this problem I would multiply 21 x 34= 714 then I would divide it by 14 which would get me 51. There would be 51 blocks in each group!
Answer:
72.5
122
Step-by-step explanation:
Half-life for McGill-23 is 145 years. What is the k value?
half of 145 = 72.5
145 - 23 = 122
Hope I did the right thing
Hope this helps ❤️
