Answer:
Please find the punnet square to this question as an attachment
F1 generation:
genotype = BW
Phenotype = Erminette offsprings
F2 generation:
genotype = BB (1): BW(2): WW(1)
Phenotype = 1 Black, 2 Erminette, 1White
Explanation:
This question involves a gene coding for feather color in chickens. The allele for black feathers (B) is codominant with the allele for white feathers (W) to form an erminette chicken (black and white speckles).
According to this question, a cross between a chick with black (BB) feathers and chicken with white (WW) feathers will result in an all erminette chicken (BW) in the F1 generation (see attached image)
Also, in the F2 generation got by self-crossing the Erminette genotype in the F1 generation (BW), the following genotypic and phenotypic ratios are observed:
Genotypic ratio = BB (1): BW(2): WW(1)
Phenotypic ratio = 1 Black, 2 Erminette, 1White
Conjunctiva lines the eyelids and covers the anterior sclera
The observable traits expressed by an organism are referred to as its phenotype. An organism's underlying genetic makeup, consisting of both physically visible and non-expressed alleles, is called its genotype.
Answer: freshwater lakes
<span>Fossilized fish is most likely to live in freshwater lakes.</span>
<span>Based on the fossil record, some fossils of vertebrates including fishes were found abundant in Green River Lake. It was noted for its well-preserved fish since mid of the 19th century due to its cold period and great depth of lakes. </span>