We want to see which offer is the best one to buy 40 batteries, by using algebra we will see that the best offer is offer-B
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How to find the best offer?</h3>
Here we just need to see which would be the cost of 40 batteries which each offer.
For offer-A, a pack of 4 costs £2.52 and we have 1/3 off.
For 40 batteries the cost will be 10 times the above quantity, we get:
10* £2.52 = £25.20
But there is a 1/3 off, so the cost would be 2/3 of the above quantity:
£25.20*(2/3) = £16.80
For offer-B we know that a pack of 5 costs £2.75, so you need to buy 8 of these. And for each 3 you get one free, so you need to buy 6 (and get 2 free ones). The cost of 6 of these is:
6*£2.75 = $16.50
From this, we can conclude that offer-B is the best one.
If you want to learn more about algebra, you can read:
brainly.com/question/8120556
From 1st condition:
3^(x+1)=81
Take log on both sides,
➡ log [3^(x+1)]=log81
Use the property: log(x^a)=a logx
➡ (x+1) log 3=log(3⁴)
➡ (x+1) log 3=4×log 3
➡ (x+1)=4 (log 3 /log 3)
➡ x+1=4
➡ x=3➡↪➡↪ ANS
From 2nd condition, (Same process are repeated)
81^(x-y)=3
➡ 3^4(x-y)=3
➡ log [3^4(3-y)]=log 3
➡ 4(3-y) log 3=log 3
➡ (3-y)=(log 3)/(4log 3)
➡ 3-y=(1/4)
➡ y=11/4 ➡↪➡↪ ANS
Answer:
first we will make them like fractions
so 1/5= 2/10 so it will be
2/10+3/10= 5/10
HOPE IT HELPS
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The answer is
1/3^3
And
1/27
And
3^-3
