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2 years ago

Rotate trapezoid ABCD 90° clockwise around the origin. What are the coordinates of D’?

Mathematics

1 answer:

wolverine [178]2 years ago

3 0

When you rotate it clockwise
lets say you have thepoint (a,b)
when you rotate it clockwise you are left with the points (-b,-a)

so

D=(-4,0)
therefor
negative and switch
new point is
(0,4)

answe is C

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Write in slope-intercept form an equation of the line that passes through the given points.

KonstantinChe [14]

Y=1/3x-3 Is the answer to it

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3 years ago

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Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL

Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

J(2;5); K(1;1)

=> JK = $\sqrt{(1-2)^{2} + (1-5)^{2} } = \sqrt{(-1)^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

J(2;5); L(5;2)

=> JL = $\sqrt{(5-2)^{2} + (2-5)^{2} } = \sqrt{3^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

K(1;1); L(5;2)

=> KL = $\sqrt{(5-1)^{2} + (2-1)^{2} } = \sqrt{4^{2}+1^{2} } = \sqrt{1+16}=\sqrt{17}$

In the triangle QNP, the sides can be calculate as following:

Q(-4;4); N(-3;0)

=> QN = $\sqrt{[-3-(-4)]^{2} + (0-4)^{2} } = \sqrt{1^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

Q (-4;4); P(-7;1)

=> QP = $\sqrt{[-7-(-4)]^{2} + (1-4)^{2} } = \sqrt{(-3)^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

N(-3;0); P(-7;1)

=> NP = $\sqrt{[-7-(-3)]^{2} + (1-0)^{2} } = \sqrt{(-4)^{2}+1^{2} } = \sqrt{16+1}=\sqrt{17}$

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

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3 years ago

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If f(x) = -(-2x - 5), what is f(-5)?

sammy [17]

Answer:

f(-5)=-5

Step-by-step explanation:

f(-5)= -((-2)(-5)-5)

= -(10-5)

= -(5)

= -5

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2 years ago

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In the given figure, mWY = 76° and mXZ = 112. What is the difference of the measures of angle WPY and angle XPY?

skelet666 [1.2K]

Please consider the attached image for complete question.

We have been given that measure of arc WY is 76° and and measure of arc XZ is 112°. We are asked to find the difference of of the measures of angle WPY and angle XPY.

First of all we will find the measure of angle WPY using intersecting secants theorem. Intersecting secants theorem states that measure of angle formed by two intersecting secants inside a circle is half the sum of intercepting arcs.

$m\angle WPY=\frac{1}{2}(\widehat{WY}+\widehat{XZ})$