The product of the third and the sixth terms of an arithmetic sequence is 406. The

Mathematics

1 answer:

yuradex [85]3 years ago

7 0

Answer:

The product of the third by the sixth term of an arithmetic progression is 406. The division of the ninth term of the progression by the fourth term gives a quotient 2 and a remainder 6. Find the first term and the difference of the progression.

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Right answer no lin or bot

kvv77 [185]

Answer:

$2\frac{9}{10} or\frac{29}{10}$

Step-by-step explanation:

Hope this helps! Have a great day ahead. Happy halloween :) Stay Safe <33

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Solve for x: −5|x + 1| = 10

Elena-2011 [213]

$|a|\geq0\ for\ a\in\mathbb{R}\\\\|a|=a\ for\ a\geq0\\\\|a|=-a\ for\ a$

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The angles of a quadrilateral measure 80° 100° 100° and 80° In this order what kind of quadrilateral has this shape?

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brainliest? :)

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3 years ago

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Plz help me NOW I will mark you brainliest

puteri [66]

Let x be the percentage of p.
Therefore,
$m\% \: \: of \: \: n = x\% \: \: of \: \: p \\ = > \frac{mn}{100} = \frac{px}{100} \\ = > mn = \frac{px}{100} \times 100 \\ = > mn = px \\ = > \frac{mn}{p} = x$

<u>Answer:</u>

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2 years ago

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