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jenyasd209 [6]
3 years ago
13

A research submarine has a 30-cm-diameter window that is 8.6cm thick. The manufacturer says the window can withstand forces up t

o 1.2×10^6 N . What is the submarine's maximum safe depth in salt water?
The pressure inside the submarine is maintained at 1.0 atm.
Physics
1 answer:
Triss [41]3 years ago
6 0
What is missing is the density of salt water. Let's denote it ρ. 
<span>The pressure at depth d then is: </span>
<span>p = p0 + ρ g d </span>
<span>, where p0 is the atmospheric pressure at the surface of the sea. We assume it is equal to the 1 atm inside the sub. </span>

<span>Hence the pressure difference between inside and outside of the window is: </span>

<span>Δp = ρ g d </span>

<span>The force on the window is this pressure difference, multiplied by the area of the circular window of diameter D. The latter equals </span>
<span>A = ¼ π D². </span>

<span>So </span>
<span>F = p A = ¼ π D ²ρ g d. </span>
<span>This should be less than Fmax. </span>

<span>Hence d < Fmax / (¼ π D ²ρ g ). </span>
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v₀ = initial speed as tarzan grabs the vine = 5.3 m/s

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Answer:

  L = 5076.5 kg m² / s

Explanation:

The angular momentum of a particle is given by

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         L = r m v sin θ

the bold are vectors, where the angle is between the position vector and the velocity, in this case it is 90º therefore the sine is 1

as we have two bodies

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let's find the distance from the center of mass, let's place a reference frame on one of the masses

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        x_{cm} = 13.1 / 2 = 6.05 m

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          L = 2  6.05  74.3  5.65

          L = 5076.5 kg m² / s

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