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Setler [38]
3 years ago
5

An electric kettle is rated at 2 kW when connected to a 230 V electrical supply

Physics
1 answer:
Oliga [24]3 years ago
6 0

Explanation:

a) P = IV

2000 W = I (230 V)

I = 8.7 A

b) The fuse must be rated for a higher current than the kettle, so use the 13A fuse.

c) Double insulation means there are two layers of insulation, insuring that the wires cannot touch the outer casing of the kettle and protecting the user from electrical shock.

d) V = IR

230 V = (8.7 A) R

R = 26.5 Ω

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Solve for the tension in the left rope, TL, in the special case that x=0. Be sure the result checks with your intuition. Express
Tatiana [17]

Answer:

at x=0

T_{l}=W*L/L

and

T_{l}=W-T_{r}

Explanation:

Solve for the tension in the left rope, TL, in the special case that x=0. Be sure the result checks with your intuition. Express your answer in terms of W and the dimensions L and x. Not all of these variables may show up in the solution.

moments is the product of force and the perpendicular distance in line of the action of the given force

from the principle of moments which states that the sum of clockwise moments ,must be equal to the sum of anticlockwise moments.

also, sum of upward forces must be equal to sum of downward forces

Going by the aforementioned,

taking moments about T_{r}

W*(l-x)=T_{l}*(L)

T_{l}=W*(L-x)/(L)..............1

at x=0

T_{l}=W*L/L

also

T_{l}+ T_{r}=W

T_{l}=W-T_{r}

3 0
4 years ago
Calculate the true mass (in vacuum) of a piece of aluminum whose apparent mass is 4.5000 kg when weighed in air. The density of
sasho [114]

Answer:

m = 4.5021 kg

Explanation:

given,

Apparent mass of aluminium = 4.5 kg

density of air = 1.29 kg/m³

density of aluminium = 2.7 x 10⁷ kg/m³

true mass of the aluminium = ?

Weight in Vacuum

W = m g

W = ρV g

Air buoyancy acting on aluminium

B = ρ₀V g

Volume is the same in both cases since the volume of the aluminum

displaces an equal amount of volume air.

Apparent weight:

ρV g − ρ₀V g = 4.5 g

ρV − ρ₀V = 4.5

V = \dfrac{4.5}{\rho - \rho_0}

m = ρV

m = \dfrac{4.5\times \rho}{\rho - \rho_0}

m = \dfrac{4.5\times 2700}{2700 - 1.29}

m = 4.5021 kg

4 0
3 years ago
What mechanical layer lies below the lithosphere
joja [24]
The <span>asthenosphere is under the lithosphere.</span>
3 0
3 years ago
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A hydrogen atom is in its ground state when its orbital electron:
Harlamova29_29 [7]
It is in its ground state when its orbital electron is at its lowest energy amount. 
8 0
3 years ago
A car goes from rest to a velocity of 108 km/h north in 10s what is the car's acceleration in m/s2
fomenos

initial velocity of the car given as

v_i = 0

final velocity is given as

v_f = 108 km/h

as we know that

1 km/h = 0.277 m/s

now we can convert final speed into m/s

v_f = 108 * 0.277 = 30 m/s

now acceleration is rate of change in velocity

a = \frac{v_f - v_i}{t}

a = \frac{30 - 0}{10}

a = 3 m/s^2

so the acceleration of the car is 3 m/s^2

7 0
3 years ago
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