D.
All follow an elliptical path that has two foci, rather than a circular path.
Kepler found paths are elliptical, not circular
Answer:
speed of electrons = 3.25 ×
m/s
acceleration in term g is 3.9 ×
g.
radius of circular orbit is 2.76 ×
m
Explanation:
given data
voltage = 3 kV
magnetic field = 0.66 T
solution
law of conservation of energy
PE = KE
qV = 0.5 × m × v²
v =
v =
v = 3.25 ×
m/s
and
magnetic force on particle movie in magnetic field
F = Bqv
ma = Bqv
a =
a =
a = 3.82 ×
m/s²
and acceleration in term g
a =
a = 3.9 ×
g
acceleration in term g is 3.9 ×
g.
and
electron moving in circular orbit has centripetal force
F =
Bqv =
r =
r =
r = 2.76 ×
m
radius of circular orbit is 2.76 ×
m
Answer:
Because you have a greater understanding of the mentality and conduct of individuals you care about, you are better able to understand their perspective and are more likely to recognize possible situational factors for their behavior.
The distance covered by the acorn is 3.136 m.
<u>Explanation:</u>
The time taken for the acorn to hit the ground is 0.8 s. As it is a free fall, the acorn will be completely under the influence of gravity. So the acceleration will be acceleration due to gravity.
Then using the second law of equation,

Since the initial velocity and time is zero, then the time taken to reach the ground is stated as 0.8 s, so

So the distance covered by the acorn is 3.136 m.