Is there any possibility to make 100% efficient system

-Dominant- [34]

The answer's 25,000 joules
half m v squared
half 2000, x 5 squared

7 0

3 years ago

There is a single electron at a distance from the point charge. On which of the following quantities does the force on the elect

Anon25 [30]

Answer:

The following situations apply: A, B, D.

Explanation:

The following situations apply: A, B, D.

1.) The electric force on the electron depends on A because E= F/q and thus, F=kqq_o/r^2 Ta. As you can see, the electric force depends on r^2, which is the distance between the positive charge and the negative charge, squared.

2.) As for B, the electric force on the electron depends on its charge as you can see from equation above.

3.) As for C, mass doesn't appear anyway in the equation for Force, thus, the mass doesn't matter.

4.) For D, yes, see equation for Force.

5.) For E, no

6.) For F, r in the equation for the force refers to the distance between both charges, not the radius of either charge. Thus, F doesn't matter.

7.) For G, no.

6 0

3 years ago

Read 2 more answers

From class, weight is a measurement of the force of

Ahat [919]

Answer:

the answer is well known as gravity

7 0

3 years ago

A car accelerates uniformly from rest and

miv72 [106K]

Answer:

29.75 revolutions

Explanation:

The kinematic formula for distance, given a uniform acceleration a and an initial velocity v₀, is

$d=v_0t+\frac{1}{2}at^2$

This car is starting from rest, so v₀ = 0 m/s. Additionally, we have a = 9.2/9.7 m/s² and t = 9.7 s. Plugging these values into our equation:

$d=0t+\frac{1}{2}\left(\frac{9.2}{9.7}\right)(9.7)^2\\d=\frac{1}{2}(9.2)(9.7)\\d=4.6(9.7)\\d=44.62$

So, the car has travelled 44.62 m in 9.7 seconds - we want to know how many of the tire's <em>circumferences</em> fit into that distance, so we'll first have to calculate that circumference. The formula for the circumference of a circle given its diameter is $c=\pi{d}$ , which in this case is 47.8π cm, or, using π ≈ 3.14, 47.8(3.14) = 150.092 cm.

Before we divide the distance travelled by the circumference, we need to make sure we're using the same units. 1 m = 100 cm, so 105.092 cm ≈ 1.5 m. Dividing 44.62 m by this value, we find the number of revs is

$44.62/1.5\approx29.75$ revolutions