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inessss [21]
3 years ago
12

HIJ Inc. Purchases a truck for $32,000 on January 1st, 2019. The vehicle is estimated to have a useful life of 15 years, at whic

h point it will have a residual value of $2,000. HIJ Inc. Uses the straight-line method to account for depreciation. What is the accumulated depreciation and book value respectively in 8 years? Select one:

Mathematics
1 answer:
Artyom0805 [142]3 years ago
5 0

Answer:

#See solution and attached for details

Step-by-step explanation:

Straight line method assumes a gradual depreciation in value of an asset's useful life.

-It's calculated by dividing the difference between an asset's cost and its expected salvage value by the number of years it is expected to be used.

Dep/yr=(A-Salvage)/n\ \ \ \ \ \ n=15, A=32000\\=(32000-2000)/15\\=2000

From our calculation, depreciation is $2,000 per year

Accumulated depreciation=8*2000=$16,000

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A conservative estimate of the number of stars in the universe is 6 x 10^22. The average human can see about 3,000 stars at nigh
Ilia_Sergeevich [38]

2 \times 10^{19} times more stars are there in universe compared to human eye can see

<h3><u>Solution:</u></h3>

Given that, conservative estimate of the number of stars in the universe is 6 \times 10^{22}

The average human can see about 3,000 stars at night with only their eyes

To find: Number of times more stars are there in the universe, compared to the stars a human can see

Let "x" be the number of times more stars are there in the universe, compared to the stars a human can see

Then from given statement,

\text{Stars in universe} = x \times \text{ number of stars human can see}

<em><u>Substituting given values we get,</u></em>

6 \times 10^{22} = x \times 3000\\\\x = \frac{6 \times 10^{22}}{3000}\\\\x = \frac{6 \times 10^{22}}{3 \times 10^3}\\\\x = 2 \times 10^{22-3}\\\\x = 2 \times 10^{19}

Thus 2 \times 10^{19} times more stars are there in universe compared to human eye can see

5 0
4 years ago
What is the value of C in the matrix equation below?
lara [203]

Given:

The matrix equation is:

\begin{bmatrix}-18&3&5\end{bmatrix}-C=\begin{bmatrix}-22&1&12\end{bmatrix}

To find:

The value of matrix C.

Solution:

Let A=\begin{bmatrix}-18&3&5\end{bmatrix},B=\begin{bmatrix}-22&1&12\end{bmatrix}. Then the given equation can be rewritten as

A-C=B

-C=B-A

C=-(B-A)

C=A-B

On substituting the values of the matrices, we get

C=\begin{bmatrix}-18&3&5\end{bmatrix}-\begin{bmatrix}-22&1&12\end{bmatrix}

C=\begin{bmatrix}-18-(-22)&3-1&5-12\end{bmatrix}

C=\begin{bmatrix}-18+22&2&-7\end{bmatrix}

C=\begin{bmatrix}-4&2&-7\end{bmatrix}

Therefore, the correct option is C.

6 0
3 years ago
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What is 2x-6+7=4x+4-2 equal to?
Hatshy [7]

Answer:

x=(-2)

Step-by-step explanation:

subtract 4x from 2x

-6+7=1  4-2=2  subtract 1 from 2

-2x=1  x=-2

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3 years ago
Julie is looking through the supermarket catalogue for her favourite cookies-and-cream ice-cream.
Nikitich [7]

Answer:

needs $1.62 saving

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1.2 litres for triple chocolate is $3.78. $5.40 minus $3.78. is $1.62

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2 years ago
Help me round this math question
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Answer:

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Explanation:

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3 0
3 years ago
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