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lara31 [8.8K]
2 years ago
14

What is the Domain and Range of the function f(x)

le="\sqrt{x-7} +9" alt="\sqrt{x-7} +9" align="absmiddle" class="latex-formula">?
Mathematics
1 answer:
omeli [17]2 years ago
5 0

For the given function, the domain is D : { x ≥ 7} and the range is R: { y ≥ 9}

<h3>How to get the domain and range?</h3>

Here we have a square root, remember that the argument of the square root must be equal or larger than zero, so the domain is such that:

x - 7 ≥ 0.

Solving for x we get:

x ≥ 0 + 7

Then the domain is:

x ≥ 7

To get the range, we evaluate in the minimum of the domain:

f(7) = √(7 - 7) + 9 = 9

Then the range is the set of all values larger than 9, because the function is increasing.

So the range is R: y ≥ 9.

If you want to learn more about domain and range:

brainly.com/question/10197594

#SPJ1

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7+2x/3 =5 what’s the answer
Jobisdone [24]
<h3>Answer:</h3>

4

<h3>Step-by-step explanation:</h3>

\sf  \frac{7 + 2x}{3}  = 5

\sf  = 7 + 2x = (5 \times 3)

\sf  = 7 + 2x = 15

\sf  = 2x = 15 - 7

\sf  = 2x = 8

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Can somebody find the solution to this question
AleksAgata [21]
<h3>Answer: Solution is x = -2</h3>

You have two equations with y1 = f(x) and y2 = g(x).

We're looking for the values of x such that f(x) = g(x). This is the same as trying to solve y1 = y2.

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