Answer:
<h2>
3,654 different ways.</h2>
Step-by-step explanation:
If there are 30 students in a class with natasha in the class and natasha is to select four leaders in the class of which she is already part of the selection, this means there are 3 more leaders needed to be selected among the remaining 29 students (natasha being an exception).
Using the combination formula since we are selecting and combination has to do with selection, If r object are to selected from n pool of objects, this can be done in nCr number of ways.
nCr = n!/(n-r)!r!
Sinca natasha is to select 3 more leaders from the remaining 29students, this can be done in 29C3 number of ways.
29C3 = 29!/(29-3)!3!
29C3 = 29!/(26!)!3!
29C3 = 29*28*27*26!/26!3*2
29C3 = 29*28*27/6
29C3 = 3,654 different ways.
This means that there are 3,654 different ways to select the 4 leaders so that natasha is one of the leaders
The other commentor is right. The correct answer is 2-i
The second follow-up question is the second option
f(x) = (x<span> – (2 + </span>i))(x<span> – (2 –</span><span> i</span>))(x<span> – 5)
</span>The third follow-up question has these three answers.
9x^2
25x
25
The answer is A, B(4, 4) and D(4, -3).
Hope I helped!!!! :D
Easy! Just substitute.
That will be 3 + 8 * 4
Remember PEMDAS? Multiplication comes before addition, so FIRT MULTIPLY.
3+ 32= 35
Final answer= 35
