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3 years ago

Choose the equation below that represents the line passing through the point -3, -1 with a slope of four

Mathematics

1 answer:

Agata [3.3K]3 years ago

7 0

Y- y1 = m (x-x1)
y+1 = 4(x+3)
y+1=4x+12
y=4x+11

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Find the sum of the first 6 terms in the sequence -5 -25 -125 -625

sashaice [31]

This is a geometric sequence, so use the formula for the sum of a geometric sequence:
Sum = (a(r^n - 1))/(r - 1)
where a is the first term, -5
r is the common ratio, 5
and n is the number of terms

Thus,
Sum = ((-5)(5^6 - 1))/(5-1) = -19530

5 0

3 years ago

You have a new mobile phone. The phone costs £140 and then you pay for a one year contract at £15 per month. How much do you pay

netineya [11]

It is the amount you pay each month times 12
15x12=£180

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3 years ago

If 50 percent of x=66 then x =

sasho [114]

Answer:

132

Step-by-step explanation:

50 % means half

so 66 is half of whatever x is.

to find x you have to multiply 66 by 2 or add 66 to 66 which will give you 132 either way.

Hope this helps you! have an amazing day :)

7 0

2 years ago

Read 2 more answers

The value of 7 in 17.92 is times as much value of 7 in 92.17

koban [17]

100
.. . . . . . . . .

3 0

3 years ago

Which statement describes if there is an extraneous solution to the equation √x-3 = x-5? A. there are no solutions to the equati

Brrunno [24]

Remember that an extraneous solution of an equation, is the solution that emerges from solving the equation but is not a valid solution.

Lets solve our equation to find out what is the extraneous solution:
 $\sqrt{x-3} =x-5$
$(\sqrt{x-3})^2 =(x-5)^2$
$x-3=x^2-10x+25$
$x^2-11x+28=0$
$(x-4)(x-7)=0$
$x-4=0$ and $x-7=0$
$x=4$ and $x=7$

So, the solutions of our equation are $x=4$ and $x=7$ . Lets replace each solution in our original equation to check if they are valid solutions:
- For $x=7$
$\sqrt{x-3} =x-5$
$\sqrt{7-3} =7-5$
$\sqrt{4} =2$
$2=2$
We can conclude that 7 is a valid solution of the equation.

- For $x=4$
$\sqrt{x-3} =x-5$
$\sqrt{4-3} =4-5$
$\sqrt{1} =1$
$1 \neq 1$
We can conclude that 4 is not a valid solution of the equation; therefore, 4 is a extraneous solution.

We can conclude that the correct answer is: D. the extraneous solution is x = 4

7 0

2 years ago