Answer:
B
Step-by-step explanation:
2.0 x 10^7
Answer:
Step-by-step explanation:
Given
Required
Solve
We have:
Collect like terms
So:
Answer:
The coordinates of H′ are (-2,0).
Step-by-step explanation:
It is given that square EFGH stretches vertically by a factor of 2.5 with respect to the x-axis to create rectangle E′F′G′H′.
If a figure stretches vertically by a factor of 2.5 with respect to the x-axis, then the x-coordinates remains same and the points which lie on the axis are also remains the same after stretch.
It is given that the coordinates of H are (-2,0). This point lie on the x-axis, therefore it will remains the same after stretch.
Therefore the coordinates of H′ are (-2,0).
Answer: t = 6 s
Step-by-step explanation:
When Rose hit the water, the height of the jump is 0, so: h(t) = 0.
Resolving it, we have:
-16t² + 16t + 480 = 0
To simplify the second degree equation, divided it by 16:
-t² + t + 30 = 0
Now, solve the equation using Bhaskara:
Δ = 1² - 4. (-1) . 30
Δ = 1 + 120
Δ = 121
t = 
t₁ = 
= - 5
t₂ = 
= 6
Since time can be negative, it took t = 6s for Rose to hit the water.
Answer:
I believe that B is the correct answer!
Step-by-step explanation:
The (x+5) can cancel
Then in the numerator (x^2-25) can be factored into (x-5)(x+5) through difference of squares.
Then in the denominator the (x-5)^2 can be stretched out to (x-5)(x-5)
Lastly the (x-5) on the top and bottom will cancel resulting in result B
I hope this helped!
