Ill give 5 starts to who ever helps me.

Mathematics

1 answer:

Ivahew [28]2 years ago

5 0

No it doesn't be i thought that it you would have to find a domain but i couldn't

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Points P, Q, and S are collinear. What is m∠SQR?

RideAnS [48]

Answer:

m∠SQR = 74°

Step-by-step explanation:

Points P, Q and R are collinear.

Therefore, angles PQR and angle RQS are the linear pair of angles.

Since linear pair of angles are supplementary angles.

m∠PQR + m∠RQS = 180°

By substituting the measures of the given angles,

(3m + 1) + (2m + 4) = 180

5m + 5 = 180

5m = 180 - 5

5m = 175

m = $\frac{175}{5}$

m = 35

Since, m∠SQR = (2m + 4)°

= (2×35) + 4

= 74°

Therefore, m∠SQR = 74° is the answer.

8 0

3 years ago

Help me please i dont understand it

Mekhanik [1.2K]

Answer:

6 u^4 v^2 (5 y^9 + 4 u^4 v^6)

Step-by-step explanation:

factoring basically means to take out the things that they have in common and put it outside of the parenthesis

when my says something like u^4 it means 4 is an exponent of u

8 0

2 years ago

Rewrite the form In exponential form: Log100 = x

andrey2020 [161]

Answer:

$10^x=100$

Step-by-step explanation:

You know how subtraction is the opposite of addition and division is the opposite of multiplication? A logarithm is the opposite of an exponent. You know how you can rewrite the equation 3 + 2 = 5 as 5 - 3 = 2, or the equation 3 × 2 = 6 as 6 ÷ 3 = 2? This is really useful when one of those numbers on the left is unknown. 3 + _ = 8 can be rewritten as 8 - 3 = _, 4 × _ = 12 can be rewritten as 12 ÷ 4 = _. We get all our knowns on one side and our unknown by itself on the other, and the rest is computation.

We know that $3^2=9$ ; as a logarithm, the exponent gets moved to its own side of the equation, and we write the equation like this: $\log_3{9}=2$ , which you read as "the logarithm base 3 of 9 is 2." You could also read it as "the power you need to raise 3 to to get 9 is 2."

One historical quirk: because we use the decimal system, it's assumed that an expression like $\log1000$ uses base 10, and you'd interpret it as "What power do I raise 10 to to get 1000?"

The expression $\log100=x$ means "the power you need to raise 10 to to get 100 is x," or, rearranging: "10 to the x is equal to 100," which in symbols is $10^x=100$ .