Which electron configuration represents the electrons in an atom of sulfur in an excited state? 2 – 8

Which procedures were followed in this lab to decrease experimental error? Check all that apply.

Fantom [35]

Answer:

theres nothin to check off

Explanation:

u didnt pin anything

ily and God does too

5 0

3 years ago

What will increase the salt concentration in seawater?

MA_775_DIABLO [31]

Answer:

Evaporation process

Explanation:

The evaporation process is responsible for the increase in the concentration of salt in the oceans or seawater.

Within the ocean there are certain places where there occurs little or no rainfall. The temperature in this region is relatively high and dry, due to which there occurs the process of evaporation. Because of the absence of rainfall, the rate of evaporation is higher in this region compared to the rate of precipitation. So when this process takes place, it eliminates the water quantity present in it, resulting in the formation of salts.

The salinity of the ocean increases because of the high rate of evaporation of the ocean water as well as forming of the sea ice.

8 0

4 years ago

The unique properties of water enable life to exist on Earth. Which of these is a property of pure water?

Lera25 [3.4K]

Answer:

Capillarity , Adhesion and cohesion . The unique property of water enable life to exist . The most important property of water is movement of materials due to water , maintenance and growth and reproduction .

Explanation:

3 0

4 years ago

Read the statement.

lina2011 [118]

Answer:

60 g/L is the final concentration of NaI solution .

Explanation:

Molarity of NaI solution before evaporation = $M_1= 0.2 M$

Volume of NaI solution before evaporation = $V_1= 2.0 L$

Molarity of NaI solution after evaporation = $M_2= ?$

Volume of NaI solution after evaporation = $V_2= 1.0 L$

$M_1V_1=M_2V_2$ ( dilution)

$M_2=\frac{M_1V_1}{V_2}=\frac{0.2 M\times 2.0 L}{1.0 L}=0.4 M$

Molar mass of NaI = 150 g/mol

Concentration of NaI after evaporation :

0.4 M × 150 g/mol = 60 g/L

60 g/L is the final concentration of NaI solution .

4 0

3 years ago

Two gases, A and B, are at equilibrium in a sealed cylinder. Individually, gas A is colorless, while gas B is dark colored. The

Dmitriy789 [7]

Answer:

(a) color

(b) endothermic

(c)

b The ΔH value would have the same magnitude value but opposite sign.

c The K expression would be inverted.

Explanation:

Let's consider the following reaction at equilibrium.

A(g) ⇄ 2 B(g)

colorless dark colored

(a) The cylinder should appear (color or colorless)

At equilibrium, there is a mixture of A and B, so the cylinder should appear colored.

(b) When the system is cooled, the cylinder's appearance becomes very light colored. Therefore, the reaction must be (endothermic or exothermic)

According to Le Chatelier's Principle when a perturbation is made to a system at equilibrium it will react to counteract such effect. When the system is cooled, it will tend to increase the temperature by releasing heat. In this case, the reaction is endothermic so when the reverse reaction is favored, colorless A is favored as well.

Suppose the reaction equation were written as follows: 2 B(g) ⇄ A(g)

(c) Which of these statements would then be true?

a The value of K would not change. FALSE. The new K would be the inverse of the direct K.

b The ΔH value would have the same magnitude value but opposite sign. TRUE. This is stated by Lavoisier-Laplace Law.

c The K expression would be inverted. TRUE. What was product before now is reactant and vice-versa.

d The color of the cylinder would be darker. FALSE. Changing the way the reaction is expressed has no effect on the equilibrium.

7 0

4 years ago

Which electron configuration represents the electrons in an atom of sulfur in an excited state? 2 – 8 – 6