Answer:
The table that represents the conditional relative frequency is:
A B Total
C 0.25 0.75 1.0
D 0.35 0.65 1.0
Total 0.30 0.70 1.0
Step-by-step explanation:
We know that a conditional relative frequency table is one:
In which the entries in each row is divided by the row total .
OR
In which the entries in each column is divided by the column total.
i.e. the frequency or quantity of an item is being compared either to row or to the column total.
Hence, from the given options, the table that represent the conditional relative frequency is:
A B Total
C 0.25 0.75 1.0
D 0.35 0.65 1.0
Total 0.30 0.70 1.0
Answer:
The equation of the line is 
Step-by-step explanation:
Equation of a line:
The equation of a line has the following format:

In which m is the slope and b is the y-intercept(the value of y when x = 0).
Perpendicular lines:
If two lines are perpendicular, the multiplication of their slopes is -1.
Line perpendicular to y = 4x + 4.
This line has slope 4, so our line will have slope:


So

Through (0, -3)
This means that 
So

Answer:
Apply BODMAS
Step-by-step explanation:
PLEASE FIND THE PICTURE BELLOW
SOLUTION STEPS
(4⋅2−10x−24)(2x+3)
Multiply 4 and 2 to get 8.
(8−10x−24)(2x+3)
Subtract 24 from 8 to get −16.
(−16−10x)(2x+3)
Apply the distributive property by multiplying each term of −16−10x by each term of 2x+3.
−32x−48−20x
2
−30x
Combine −32x and −30x to get −62x.
−62x−48−20x
2
Answer:
10x + 5
Step-by-step explanation:
x = some number
10x = 10 multiplied by 'x'
10x+5 = five more than 10 multiplied by some number
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dy
Find —— for an implicit function:
dx
x²y – 3x = y³ – 3
First, differentiate implicitly both sides with respect to x. Keep in mind that y is not just a variable, but it is also a function of x, so you have to use the chain rule there:

Applying the product rule for the first term at the left-hand side:
![\mathsf{\left[\dfrac{d}{dx}(x^2)\cdot y+x^2\cdot \dfrac{d}{dx}(y)\right]-3\cdot 1=3y^2\cdot \dfrac{dy}{dx}-0}\\\\\\ \mathsf{\left[2x\cdot y+x^2\cdot \dfrac{dy}{dx}\right]-3=3y^2\cdot \dfrac{dy}{dx}}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cleft%5B%5Cdfrac%7Bd%7D%7Bdx%7D%28x%5E2%29%5Ccdot%20y%2Bx%5E2%5Ccdot%20%5Cdfrac%7Bd%7D%7Bdx%7D%28y%29%5Cright%5D-3%5Ccdot%201%3D3y%5E2%5Ccdot%20%5Cdfrac%7Bdy%7D%7Bdx%7D-0%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7B%5Cleft%5B2x%5Ccdot%20y%2Bx%5E2%5Ccdot%20%5Cdfrac%7Bdy%7D%7Bdx%7D%5Cright%5D-3%3D3y%5E2%5Ccdot%20%5Cdfrac%7Bdy%7D%7Bdx%7D%7D)
dy
Now, isolate —— in the equation above:
dx


Compute the derivative value at the point (– 1, 2):
x = – 1 and y = 2

I hope this helps. =)
Tags: <em>implicit function derivative implicit differentiation chain product rule differential integral calculus</em>