<span>Hepatic encephalopathy is a condition seen patients
with liver dysfunction and this condition describe a spectrum of reversible
neuropsychiatric abnormalities which implies that altered brain function which
is due to metabolic abnormalities. However, the administration of lactulose
causes reduction in the urea production rate which is consistent with the
reduced entry of ammonia into portal blood.</span>
Weight is measured in Newtons, mass is measured in kilograms, mass does not change when gravity changes; weight does, mass is the amount of matter in an object, and weight is a gravitational force
The hormone is ANTIDURETIC HORMONE, ADH.
The collecting duct and the distal convoluted tubules vary in their permeability to water based on the quantity of ADH present. The collecting duct becomes more permeable to water when the ADH production increases. As the ADH production decrease, the urine volume increases. <span />
I'm assuming there is a graph to go along with the question but as a guess, The numbers of lynx and rabbits flow as opposites when rabbit population goes up soon after the lynx population wil also go up due to increase in food, then the rabbit population will go down due to the increase in predators. This patern will continue on.
Answer:
![\large\boxed{\large\boxed{107g}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Clarge%5Cboxed%7B107g%7D%7D)
Explanation:
The <em>vapor pressure lowering</em> is a colligative property and it follows Raoult's law.
The <em>vapor pressure lowering</em> of a solvent in a solution, ΔP, is equal to the mole fraction of the solute, Xsolute, multiplied by the vapor pressure of the pure solvent, P°.
![\Delta P=X_{solute}\times P^0](https://tex.z-dn.net/?f=%5CDelta%20P%3DX_%7Bsolute%7D%5Ctimes%20P%5E0)
ΔP and P⁰ are given:
<u>1. Mole fraction of solute</u>
Thus, you can calculate Xsolute:
![1.39mmHg=X_{solute}\times 55.32mmHg\\\\X_{solute}=0.02513](https://tex.z-dn.net/?f=1.39mmHg%3DX_%7Bsolute%7D%5Ctimes%2055.32mmHg%5C%5C%5C%5CX_%7Bsolute%7D%3D0.02513)
<u>2. Moles of solute</u>
Now you can calculate the number of moles of water and the number of moles of solute.
- Number of moles of water = mass in grams / molar mass
- Number of moles of water = 1,250g/18.015 (g/mol) = 69.3866mol
- Xsolvent = 1 - Xsolute = 1 - 0.02513 = 0.97487
- Xsolvent = moles of solvent / moles of solution
- 0.97487 = 69.3866mol / moles of solution
- moles of solution = 71.1752mol
- moles of solute = moles of solution - moles of solvent = 71.1752mol - 69.3866mol = 1.7886mol
<u>3. Mass of urea</u>
Formula:
- Mass = number of moles × molar mass
- Mass = 1.7886 mol × 60.06 g/mol = 107.42 g
You must round to 3 significant figures: 107 g