All categories

2 years ago

In the picture thank you

Mathematics

2 answers:

jonny [76]2 years ago

7 0

Answer:

1100 adults and 1400 students

Step-by-step explanation:

Let S = students and A = adults.

We have two conditions.

(1) 5S + 10A = 18 000

(2) S + A = 2500 Subtract A from each side

(3) S = 2500 – A Substitute (3) into (1)

5(2500 – A) + 10A = 18 000 Remove parentheses

12 500 – 5A + 10 A = 18 000 Combine like terms

12 500 + 5A = 18 000 Subtract 12 500 from each side

5A = 5500 Divide each side by 6

(4) A = 1100 Substitute (4) into (2)

S + 1100 = 2500 Subtract 1100 from each side

S = 1400

There were 1100 adults and 1400 students.

<em>Check: </em>

5 × 1400 + 10 × 1100 = 18 000 1400 + 1100 = 2500

7 000 + 11 000 = 18 000 2500 = 2500

1 8 000 = 18 000

dmitriy555 [2]2 years ago

5 0

Answer:

The correct answer is b) 1100 adults and 1400 students.

Step-by-step explanation:

To find this, set up a system of equations in which x is the number of students who attend and y is the number of adults who attend.

First start by creating an equation for money made.

5x + 10y = 18,000

Now write an equation for the amount that attend.

x + y = 2,500

Now multiply the bottom equation by -5 and add the equations together.

-5x - 5y = -12,500

5x + 10y = 18,000

5y = 5,500

y = 1,100

Since this is the number of adults, we can plug into an original equation to find the number of students.

x + y = 2,500

x + 1,100 = 2,500

x = 1,400

You might be interested in

The function f (t) = 12(1 +0.03) can be used to determine the population, in thousands of a town t years

Alja [10]

f= the original amount of people, a steady growth throughout the years

t=time

In 1955 the population was 12 thousand. Compared to the current population of 12.36 thousand, the population then was roughly 77%.

5 0

2 years ago

Select all of the expressions which show how to convert 2.5 yards into inches.

PIT_PIT [208]

Answer:

Step-by-step explanation:

4 0

2 years ago

If you sell 3 bags of candy, then 4 bags and finally 1 bag, how much is each bag if you collected $6.40?

mariarad [96]

Answer:

$51.2

Step-by-step explanation:

3 + 4 + 1 = 8

8 x 6.40 + 51.2

4 0

2 years ago

Read 2 more answers

There are 20 machines in a factory. 7 of the machines are defective.

adelina 88 [10]

Answer:

0.1225

Step-by-step explanation:

Given

Number of Machines = 20

Defective Machines = 7

Required

Probability that two selected (with replacement) are defective.

The first step is to define an event that a machine will be defective.

Let M represent the selected machine sis defective.

P(M) = 7/20

Provided that the two selected machines are replaced;

The probability is calculated as thus

P(Both) = P(First Defect) * P(Second Defect)

From tge question, we understand that each selection is replaced before another selection is made.

This means that the probability of first selection and the probability of second selection are independent.

And as such;

P(First Defect) = P (Second Defect) = P(M) = 7/20

So;

P(Both) = P(First Defect) * P(Second Defect)

PBoth) = 7/20 * 7/20

P(Both) = 49/400

P(Both) = 0.1225

Hence, the probability that both choices will be defective machines is 0.1225

4 0

3 years ago

The junior and senior students at Mathville High School are going to present an exciting musical entitled, "Math, What is it Goo

xeze [42]

Some parts are missing in the queston. Find attached the picture with the complete question

Answer:

$\large\boxed{\large\boxed{161}}$

Explanation:

Let's put the information in a table step-by step.

(number of remaining students)

Juniors Seniors

Condition

Initially J S

15 seniors left S - 15

Twice juniors as seniors 2(S - 15)

3/4 of the juniors left 1/4×2(S - 15)
1/3 of seniors left 2/3×(S - 15)

At the end, there were 8 more seniors than juniors:

2/3×(S - 15) - 1/4×2(S - 15) = 8

Now you have obtained one equation, which you can solve to find S, the number of senior students, and then the number of junior students.

Solve the equation:

$2/3\times (S - 15) - 1/4\times 2(S - 15) = 8$

Mutilply all by 12:

$8(S - 15)-6(S - 15)=96$

Distribution property:

$8S-120-6S-90=96$

Addtion property of equalities:

$8S-6S=96+120+90$

Add like terms:

$2S=306$

Division property of equalities:

$S=306/2=153$

That is the number of senior students that came out to the information meeting, but the number of students remaining to perform in the school musical is (from the table above):

$2/3\times (S-15)+1/4\times 2(S-15)$

Just substitute S with 153 fo find the number of students that remained to perfom in the musical:

$2/3\times (153-15)+1/4\times 2(153-15)\\ \\ 2/3(138)+1/2(138)$

$161$

5 0

2 years ago