Since there are no figures given, I will give an example.
You are given a silo that is shaped as
a closed cylinder with a conical end. The diameter of the silo is 4 ft, the
length of the cylindrical part is 6 ft, and the entire length of the silo is
10.5 ft. Suppose that you are asked to find the total volume of
grains that can be stored in the silo.
Given:
Cylinder part
D = 4 ft
H = 6 ft
Cone part
H = 10.5 – 6 = 4.5ft
D = 4ft
Required:
Volume of silo
Solution:
V of cylinder = πr²H
V of cylinder = π(4/2)²(6)
V of cylinder = 75.4 ft³
V of cone = πr²H/3
V of cone = π(4/2)²(4.5/3)
V of cone = 18.85 ft³
Total volume = 94.25 ft³
Answer:
C. 
Step-by-step explanation:
From the graph of the function, we can see that the domain of the function is 
the range of the function is 
Consider the parent function 
The domain of this function is 
the range of this function is 
The function has
the domain
and the range
All other options have different domain, or the range, or both the domain and the range.
Where r is the radius of the circle.
I think the answer would be the last one. a cylinder with radius 4 units.
Answer:
y=-3x+1
Step-by-step explanation:
plug in point into x and y, replace -4 as a +b(or any other variable to represent y intercept)
therefore,
7=-3(-2)+b
7=6+b
1=b
y=-3x+1
